Digital Electronics - Boolean Algebra and Logic Simplification - Discussion
Discussion Forum : Boolean Algebra and Logic Simplification - General Questions (Q.No. 43)
43.
Determine the binary values of the variables for which the following standard POS expression is equal to 0. 
Discussion:
19 comments Page 1 of 2.
Pavan Krishna said:
3 years ago
Correct answer: B.
A=1,B=0,C=1.
(A+B'+C)(A'+B+C'),
(1+1+1)(0+0+0),
(1)(0).
=0, ONLY B is correct.
A=1,B=0,C=1.
(A+B'+C)(A'+B+C'),
(1+1+1)(0+0+0),
(1)(0).
=0, ONLY B is correct.
VISCOS said:
6 years ago
NB:In POS form,"input with a bar " is assigned '1' and '0' if there is no bar unlike the SOP form.
(A+B'+C).(A'+B+C') = (0 + 1 + 0).(1 + 0 + 1),
So, A is correct.
(A+B'+C).(A'+B+C') = (0 + 1 + 0).(1 + 0 + 1),
So, A is correct.
Alexandar said:
6 years ago
I think A is Correct bcoz the given binary values represent the values for the inputs (A,B,C), then
(0+1+0)=> for (A+B'+C)=(0+0+0)=0&
(1+0+1)=>for (A'+B+C')=(0+0+0)=0 so;
(A+B'+C).(A'+B+C')= 0.0 = 0.
(0+1+0)=> for (A+B'+C)=(0+0+0)=0&
(1+0+1)=>for (A'+B+C')=(0+0+0)=0 so;
(A+B'+C).(A'+B+C')= 0.0 = 0.
Jorriam Tsotetsi said:
7 years ago
Both A and C are correct.
(A + B' + C)(A' + B + C'),
C=(0 + 0 + 0)(1 + 0 + 1),
=(0 + 1 + 0)(0 + 0 + 0),
=(1)(0),
=(0).
For A.
(A + B' + C)(A' + B + C'),
C=(0 + 0 + 0)(1 + 0 + 1),
=(0 + 1 + 0)(0 + 0 + 0),
=(1)(0),
=(0).
For A.
Sita said:
7 years ago
B is the correct answer.
Vaishu said:
8 years ago
Place given value into the expression and calculate the result.
Vaishali said:
8 years ago
Option A is correct. I agree.
Sam said:
8 years ago
The values of A, B, C are taken as inputs or outputs? Please explain.
Reddy said:
9 years ago
Both B and C are correct 1.0 = 0, 0.1 = 0.
GHC said:
9 years ago
Answer B is correct, where we have considered A = 1, B = 0, C = 1 as input. So A' = 0, B' = 1, C' = 0.
Put this values in the equation given in option B, perform the summation of terms individually, then multiplication of answer of two terms, which will give 0.
Put this values in the equation given in option B, perform the summation of terms individually, then multiplication of answer of two terms, which will give 0.
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