Discussion :: Boolean Algebra and Logic Simplification - General Questions (Q.No.2)
|Kailash said: (Aug 14, 2011)|
|When A=1, B=0, C=1, D=0 THEN ANS WILL BE ZERO.|
|Surya Bharathi said: (Sep 20, 2011)|
|Since B and D are not inversed their values should be 0.
A and D inversed their values should be 1.
|Prabha said: (Dec 21, 2011)|
|A is negotiate the value must be 1 so that A value will be zero same like C is negotiate the value must be 1 so that C value will be zero if all the values are zero then if we add those values we will get zero.|
|Sunellagirl said: (Aug 29, 2012)|
|Isnt A'=0 and b=1 and c'=0 and d=1?|
|Sonu said: (Sep 1, 2012)|
|Yes Sunella. You are correct. The answer is error.|
|Atoroyo David said: (Oct 10, 2012)|
|A'=1 so that A=0, C'=1 and C=0 summing up the answer is zero.|
|Vidushi said: (Apr 12, 2013)|
|As we are talking about complement so the value of a & c becomes 0 if we take them as 1. So correct answer is B.|
|Chandan said: (Mar 26, 2014)|
|A'+B+C'+D = 1'+0+1'+0 = 0+0+0+0 = 0.|
|Tuhin said: (Dec 15, 2014)|
|When you add a variable with 1 result will be equivalent to 1 as the Boolean logic A+1 = 1. Again, the result will be equivalent to variable when you'd add any variable with 0 according to Boolean 2nd logic A+0 = A (if A = 1, A + 0 = 1).
So it is proved that if we make any sum term equal to 0, value of every variable will must be 0 in that sum term. If we determine A = 0, it will be inverted into 1. But value 1 is not allowed for this term. So, the values will be A = 1, B = 0, C = 1 & D = 0.
|Sampriti said: (Aug 7, 2015)|
|Sum =0 and carry generated will be 1.|
|Ishu said: (Feb 23, 2017)|
|A=1 and C=1 so, it's complement is going to be 0.
B and D is already zero. Therefore in sum all are zero produces the result zero.
|Nitin said: (Dec 12, 2017)|
|Anyone, please explain this problem in detail.|
|Mzwakhe said: (Apr 5, 2019)|
|A = 1 it will be negated to 0 C = 1 it will also be negated to 0 therefore the expression has OR operator:
A + B + C + D = 0 when,
A = 0 B = 0 C = 0 D = 0 because OR operator takes the favor of 1,
0 + 0 + 0 + 0 = 0.
|Pavan said: (Apr 24, 2019)|
|Sop (sum of products)
POS (product of sum)
|Admin said: (Nov 4, 2019)|
|Since we have to get the sum as 0 so we have to convert all the inputs into 0 so for A bar to be 0 we have to take A as 1 and for B there is no bar means inversion so we take it as 0 only do it in the same way for the other.|
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