Data Interpretation - Table Charts - Discussion

Discussion Forum : Table Charts - Table Chart 8 (Q.No. 4)
Directions to Solve

The following table shows the number of new employees added to different categories of employees in a company and also the number of employees from these categories who left the company every year since the foundation of the Company in 1995.

Year
Managers Technicians Operators Accountants Peons
NewLeft NewLeft NewLeft NewLeft NewLeft
1995760-1200-880-1160-820-
199628012027212025610420010018496
19971799224012824012022410415288
199814888236962081002489619680
19991607225610019211227288224120
20001939628811224814426092200104


4.
What is the pooled average of the total number of employees of all categories in the year 1997?
1325
1195
1265
1235
Answer: Option
Explanation:

Total number of employees of various categories working in the Company in 1997 are:

Managers = (760 + 280 + 179) - (120 + 92) = 1007.
Technicians = (1200 + 272 + 240) - (120 + 128) = 1464.
Operators = (880 + 256 + 240) - (104 + 120) = 1152.
Accountants = (1160 + 200 + 224) - (100 + 104) = 1380.
Peons = (820 + 184 + 152) - (96 + 88) = 972.

Therefore Pooled average of all the five categories of employees working in the Company in 1997

    = 1 x (1007 + 1464 + 1152 + 1380 + 972)
5

    = 1 x (5975)
5

    = 1195.

Discussion:
16 comments Page 2 of 2.

Jimmy said:   7 years ago
It was asked only for 1997, so why consider three consecutive years?

Praveen t p said:   4 years ago
Employees at present = sum of employees till the given year.

Sheik said:   6 years ago
Can anyone please explain 1/5?

How we get this?
(1)

Pranalee said:   1 decade ago
There is no any short-cut for such questions?
(2)

Kannan said:   1 decade ago
What do you mean by pooled average?

Sushmitha said:   7 years ago
Why not taking all the amounts?


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