Data Interpretation - Table Charts - Discussion
Discussion Forum : Table Charts - Table Chart 8 (Q.No. 4)
Directions to Solve
The following table shows the number of new employees added to different categories of employees in a company and also the number of employees from these categories who left the company every year since the foundation of the Company in 1995.
Year | ||||||||||
Managers | Technicians | Operators | Accountants | Peons | ||||||
New | Left | New | Left | New | Left | New | Left | New | Left | |
1995 | 760 | - | 1200 | - | 880 | - | 1160 | - | 820 | - |
1996 | 280 | 120 | 272 | 120 | 256 | 104 | 200 | 100 | 184 | 96 |
1997 | 179 | 92 | 240 | 128 | 240 | 120 | 224 | 104 | 152 | 88 |
1998 | 148 | 88 | 236 | 96 | 208 | 100 | 248 | 96 | 196 | 80 |
1999 | 160 | 72 | 256 | 100 | 192 | 112 | 272 | 88 | 224 | 120 |
2000 | 193 | 96 | 288 | 112 | 248 | 144 | 260 | 92 | 200 | 104 |
4.
What is the pooled average of the total number of employees of all categories in the year 1997?
Answer: Option
Explanation:
Total number of employees of various categories working in the Company in 1997 are:
Managers | = (760 + 280 + 179) - (120 + 92) = 1007. |
Technicians | = (1200 + 272 + 240) - (120 + 128) = 1464. |
Operators | = (880 + 256 + 240) - (104 + 120) = 1152. |
Accountants | = (1160 + 200 + 224) - (100 + 104) = 1380. |
Peons | = (820 + 184 + 152) - (96 + 88) = 972. |
Pooled average of all the five categories of employees working in the Company in 1997
= | 1 | x (1007 + 1464 + 1152 + 1380 + 972) |
5 |
= | 1 | x (5975) |
5 |
= 1195.
Discussion:
17 comments Page 1 of 2.
Pranalee said:
1 decade ago
There is no any short-cut for such questions?
(2)
Raj442 said:
1 decade ago
Guys.. Here the data not showing the the no of employees in corresponding years. Here he has given only the no of new employees added and no of employees left. So, to find the increased employees average(pooled average means average of the increased employees), we should find the number of employees for that year. In order to find that we are calculating the members from the established year of the company.
Ex: In mechanics:
When the company started in the year 1995 the no of employees joined were 760.
In 1996 no.of employees are 760+280(new)-120(left) = 920,
In 1997 ,, , ,,, , , 920+179(new)-92(left) = 1007.
So pooled employees in the managers are 1007.
Similarly we can find the avg of all the categories.
Ex: In mechanics:
When the company started in the year 1995 the no of employees joined were 760.
In 1996 no.of employees are 760+280(new)-120(left) = 920,
In 1997 ,, , ,,, , , 920+179(new)-92(left) = 1007.
So pooled employees in the managers are 1007.
Similarly we can find the avg of all the categories.
(1)
Jay said:
4 years ago
Why do we take the data of the three years and why not just 1997.
it's kind of confusing, Please explain in detail.
it's kind of confusing, Please explain in detail.
(1)
Sheik said:
6 years ago
Can anyone please explain 1/5?
How we get this?
How we get this?
(1)
Sushmitha said:
7 years ago
Why not taking all the amounts?
Lhamo said:
3 weeks ago
Not understanding the answer. Anyone, please explain to me.
Read said:
2 years ago
A pooled average is like blending different averages to get an overall average.
Praveen t p said:
4 years ago
Employees at present = sum of employees till the given year.
Anomie said:
5 years ago
@Sheik.
1/5 is the number of categories, Average = number of all employees/ number of categories (hence: 1/5x (5975).
1/5 is the number of categories, Average = number of all employees/ number of categories (hence: 1/5x (5975).
K hari prasath pillai said:
6 years ago
For which of the above-mentioned categories the percentage increase in the number of employees working in the company from 1995 to 2000 was the maximum?
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