# Data Interpretation - Table Charts - Discussion

*Directions to Solve*

A school has four sections A, B, C, D of Class IX students.

The results of half yearly and annual examinations are shown in the table given below.

Result | No. of Students | |||

Section A | Section B | Section C | Section D | |

Students failed in both Exams | 28 | 23 | 17 | 27 |

Students failed in half-yearly but passed in Annual Exams | 14 | 12 | 8 | 13 |

Students passed in half-yearly but failed in Annual Exams | 6 | 17 | 9 | 15 |

Students passed in both Exams | 64 | 55 | 46 | 76 |

Number of students who passed half-yearly exams in the school

= (Number of students passed in half-yearly but failed in annual exams)

+ (Number of students passed in both exams)

= (6 + 17 + 9 + 15) + (64 + 55 + 46 + 76)

= 288.

Also, Number of students who passed annual exams in the school

= (Number of students failed in half-yearly but passed in annual exams)

+ (Number of students passed in both exams)

= (14 + 12 + 8 + 13) + (64 + 55 + 46 + 76)

= 288.

Since, the number of students passed in half-yearly = the number of students passed in annual exams. Therefore, it can be inferred that both the examinations had almost the same difficulty level.

Thus Statements (a), (b) and (d) are false and Statement (c) is true.

Although the same set of student given both the exam, but passing % and difficulty level can't be compared as this is qualitative relationship.

47=47 for both second and third cases of the block.

Yes you can leave that and get the answer because it is common in both.