# Data Interpretation - Table Charts - Discussion

Discussion Forum : Table Charts - Table Chart 7 (Q.No. 2)

*Directions to Solve*

A school has four sections A, B, C, D of Class IX students.

The results of half yearly and annual examinations are shown in the table given below.

Result | No. of Students | |||

Section A | Section B | Section C | Section D | |

Students failed in both Exams | 28 | 23 | 17 | 27 |

Students failed in half-yearly but passed in Annual Exams | 14 | 12 | 8 | 13 |

Students passed in half-yearly but failed in Annual Exams | 6 | 17 | 9 | 15 |

Students passed in both Exams | 64 | 55 | 46 | 76 |

2.

How many students are there in Class IX in the school?

Answer: Option

Explanation:

Since the classification of the students on the basis of their results and sections form independent groups, so the total number of students in the class:

= (28 + 23 + 17 + 27 + 14 + 12 + 8 + 13 + 6 + 17 + 9 + 15 + 64 + 55 + 46 + 76)

= 430.

Discussion:

18 comments Page 2 of 2.
Darshana said:
9 years ago

The four group are independent so the answer is sum of all the numbers.

Seetha said:
10 years ago

I think the correct answer is 336.

Total students in the class = (no of students passed in both exams + no of students failed in both exams).

Total students in the class = (no of students passed in both exams + no of students failed in both exams).

MANAV said:
10 years ago

Students failed in both the exams can't pass any or both of the exam.

Student failed in half yearly only can't failed in both exam also pass both the exam also pass annual.

So all the 4 groups are independent of each other.

NOW short cut to solve this question.

Just add all the tens position number only.

Adding row wise.

20+20+10+20 (first row over) +10+10+0+10 (second row over) +0+10+0+10 (third row over) +60+50+40+70 = 340.

Now see the options only one option is bigger than 340 tick it and enjoy the life.

Student failed in half yearly only can't failed in both exam also pass both the exam also pass annual.

So all the 4 groups are independent of each other.

NOW short cut to solve this question.

Just add all the tens position number only.

Adding row wise.

20+20+10+20 (first row over) +10+10+0+10 (second row over) +0+10+0+10 (third row over) +60+50+40+70 = 340.

Now see the options only one option is bigger than 340 tick it and enjoy the life.

ABC said:
1 decade ago

According to me the answer would be 335.

How do they form independent groups?

How do they form independent groups?

Shweta shinde said:
1 decade ago

Consider 2 venn diagrams for fail and pass students.

In fail we have failed in both, failed in annual but not half,

Failed in half but not annual, so total failed students are addition of all (28+23+17+27 + 14+12+... +16+17+... ) = x.

Now in pass venn diagram we have passed in both,

And passed in 1 and failed in other is already considered so add 64+55+... To x n we get 430.

In fail we have failed in both, failed in annual but not half,

Failed in half but not annual, so total failed students are addition of all (28+23+17+27 + 14+12+... +16+17+... ) = x.

Now in pass venn diagram we have passed in both,

And passed in 1 and failed in other is already considered so add 64+55+... To x n we get 430.

Ashish Jain said:
1 decade ago

430 is right one because there may be 4 persons e.g A, B, C and D whose result may vary.

A passed in both exams.

B failed in both exams.

C passed in half yearly and failed in annual. This is diff from B.

D failed in half yearly and passed in annual. This is diff from A.

Please correct me if I'm wrong.

A passed in both exams.

B failed in both exams.

C passed in half yearly and failed in annual. This is diff from B.

D failed in half yearly and passed in annual. This is diff from A.

Please correct me if I'm wrong.

Sai Madhav.K said:
1 decade ago

Students failed in both the exams can be inclusive of students failed in Half yearly but passed in Annual and students failed in Annual but passed in Half yearly right? Its not mentioned in the question that they perform independent operation, then how can we take that criteria into consideration?

According to the question the answer is 336. Kindly correct me if I am wrong.

According to the question the answer is 336. Kindly correct me if I am wrong.

Shashwat Shekhar said:
1 decade ago

How do they form independent groups?

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