Data Interpretation - Table Charts - Discussion
Discussion Forum : Table Charts - Table Chart 7 (Q.No. 2)
Directions to Solve
A school has four sections A, B, C, D of Class IX students.
The results of half yearly and annual examinations are shown in the table given below.
| Result | No. of Students | |||
| Section A | Section B | Section C | Section D | |
| Students failed in both Exams | 28 | 23 | 17 | 27 |
| Students failed in half-yearly but passed in Annual Exams | 14 | 12 | 8 | 13 |
| Students passed in half-yearly but failed in Annual Exams | 6 | 17 | 9 | 15 |
| Students passed in both Exams | 64 | 55 | 46 | 76 |
2.
How many students are there in Class IX in the school?
Answer: Option
Explanation:
Since the classification of the students on the basis of their results and sections form independent groups, so the total number of students in the class:
= (28 + 23 + 17 + 27 + 14 + 12 + 8 + 13 + 6 + 17 + 9 + 15 + 64 + 55 + 46 + 76)
= 430.
Discussion:
18 comments Page 1 of 2.
Arpith said:
5 years ago
To all those who consider 366 is the answer. Please note this.
Let's keep it simple.. let's assume the number of students as 4.
One student has passed in HY failed in AE.
One student has failed in HY and passed in AE.
One student has passed in both.
One student has failed in both.
Now, draw a table with this. If you have to get the class strength you need to add them 'ALL'.
Which is (1+1+1+1) = 4.
NOT, (students who passed in both) + students who (failed in both), that'll give you (1+1)= 2. Which is wrong.
Let's keep it simple.. let's assume the number of students as 4.
One student has passed in HY failed in AE.
One student has failed in HY and passed in AE.
One student has passed in both.
One student has failed in both.
Now, draw a table with this. If you have to get the class strength you need to add them 'ALL'.
Which is (1+1+1+1) = 4.
NOT, (students who passed in both) + students who (failed in both), that'll give you (1+1)= 2. Which is wrong.
(2)
Gauri Pawar said:
7 years ago
Answer is 336.
Total students = Passed in both exam + failed in both exam = 241 +95 =336.
Total students = Passed in both exam + failed in both exam = 241 +95 =336.
(1)
Prasanna said:
8 years ago
Why 430? it should be 336 (sum of students passed in both in exams + sum of students failed in both the exam).
(1)
Kusum said:
8 years ago
I think the answer should be 336.
Sivil said:
3 years ago
Nice one thanks @Arpith.
Akash Singh said:
6 years ago
HF + AF = 28+23+7+27.
HF + AP = 14+12+8+13.
HP + AF = 6+17+9+15.
HP + AP = 64+55+46+76.
Adding all equations:-
2(HP+HF+AP+AF) = 430.
HP+ HF = no. student = NS.
AP +AF = no. student = NS.
2(NS +NS) = 430.
4*NS = 430.
HF + AP = 14+12+8+13.
HP + AF = 6+17+9+15.
HP + AP = 64+55+46+76.
Adding all equations:-
2(HP+HF+AP+AF) = 430.
HP+ HF = no. student = NS.
AP +AF = no. student = NS.
2(NS +NS) = 430.
4*NS = 430.
Solomon said:
6 years ago
The answer is 335.
Rahul raghuwanshi said:
8 years ago
According to me, the answer is 336.
Suresh said:
8 years ago
Yes, you are correct @Prasanna.
Kushi said:
8 years ago
The answer should be 336. The sum of failed student and the passed one in both exams.
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