Data Interpretation - Table Charts - Discussion

Study the following table and answer the questions based on it.

Number of Candidates Appeared, Qualified and Selected in a Competitive Examination from Five States Delhi, H.P, U.P, Punjab and Haryana Over the Years 1994 to 1998

Year Delhi H.P U.P Punjab Haryana
AppQualSel AppQualSel AppQualSel AppQualSel AppQualSel
1997800085094780081082750072078820068085640070075
1998480050048750080065560062085680060070710065075
1999750064082740056070480040048650052565520035055
2000950085090880092086700065070780072084640054060
2001900080070720085075850095080570048560450060075

1. 

For which state the average number of candidates selected over the years is the maximum?

[A]. Delhi
[B]. H.P
[C]. U.P
[D]. Punjab

Answer: Option A

Explanation:

The average number of candidates selected over the given period for various states are:

For Delhi = 94 + 48 + 82 + 90 + 70 = 384 = 76.8.
5 5

For H.P. = 82 + 65 + 70 + 86 + 75 = 378 = 75.6.
5 5

For U.P. = 78 + 85 + 48 + 70 + 80 = 361 = 72.2.
5 5

For Punjab = 85 + 70 + 65 + 84 + 60 = 364 = 72.8.
5 5

For Haryana = 75 + 75 + 55 + 60 + 75 = 340 = 68.
5 5

Clearly, this average is maximum for Delhi.


Jack said: (Dec 5, 2011)  
No need to divide by 5

Renuka said: (Oct 15, 2013)  
As the total sum is high then the average is also high no need to divide with 5.

Aakansha said: (Apr 21, 2020)  
Since 5 as a denominator is the same for all four options, we can compare the no. Directly (384, 378, 361, 364) without dividing by 5.

We can see the highest is of Delhi i.e. 384. So is the answer Delhi.

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