# Data Interpretation - Table Charts - Discussion

Discussion Forum : Table Charts - Table Chart 5 (Q.No. 1)
Directions to Solve

Study the following table and answer the questions based on it.

Number of Candidates Appeared, Qualified and Selected in a Competitive Examination from Five States Delhi, H.P, U.P, Punjab and Haryana Over the Years 1994 to 1998

 Year Delhi H.P U.P Punjab Haryana App Qual Sel App Qual Sel App Qual Sel App Qual Sel App Qual Sel 1997 8000 850 94 7800 810 82 7500 720 78 8200 680 85 6400 700 75 1998 4800 500 48 7500 800 65 5600 620 85 6800 600 70 7100 650 75 1999 7500 640 82 7400 560 70 4800 400 48 6500 525 65 5200 350 55 2000 9500 850 90 8800 920 86 7000 650 70 7800 720 84 6400 540 60 2001 9000 800 70 7200 850 75 8500 950 80 5700 485 60 4500 600 75

1.
For which state the average number of candidates selected over the years is the maximum?
Delhi
H.P
U.P
Punjab
Explanation:

The average number of candidates selected over the given period for various states are:

 For Delhi = 94 + 48 + 82 + 90 + 70 = 384 = 76.8. 5 5

 For H.P. = 82 + 65 + 70 + 86 + 75 = 378 = 75.6. 5 5

 For U.P. = 78 + 85 + 48 + 70 + 80 = 361 = 72.2. 5 5

 For Punjab = 85 + 70 + 65 + 84 + 60 = 364 = 72.8. 5 5

 For Haryana = 75 + 75 + 55 + 60 + 75 = 340 = 68. 5 5

Clearly, this average is maximum for Delhi.

Discussion:
3 comments Page 1 of 1.

Aakansha said:   3 years ago
Since 5 as a denominator is the same for all four options, we can compare the no. Directly (384, 378, 361, 364) without dividing by 5.

We can see the highest is of Delhi i.e. 384. So is the answer Delhi.

Renuka said:   10 years ago
As the total sum is high then the average is also high no need to divide with 5.