Data Interpretation - Table Charts - Discussion
Discussion Forum : Table Charts - Table Chart 5 (Q.No. 3)
Directions to Solve
Study the following table and answer the questions based on it.
Number of Candidates Appeared, Qualified and Selected in a Competitive Examination from Five States Delhi, H.P, U.P, Punjab and Haryana Over the Years 1994 to 1998
Year | Delhi | H.P | U.P | Punjab | Haryana | ||||||||||
App | Qual | Sel | App | Qual | Sel | App | Qual | Sel | App | Qual | Sel | App | Qual | Sel | |
1997 | 8000 | 850 | 94 | 7800 | 810 | 82 | 7500 | 720 | 78 | 8200 | 680 | 85 | 6400 | 700 | 75 |
1998 | 4800 | 500 | 48 | 7500 | 800 | 65 | 5600 | 620 | 85 | 6800 | 600 | 70 | 7100 | 650 | 75 |
1999 | 7500 | 640 | 82 | 7400 | 560 | 70 | 4800 | 400 | 48 | 6500 | 525 | 65 | 5200 | 350 | 55 |
2000 | 9500 | 850 | 90 | 8800 | 920 | 86 | 7000 | 650 | 70 | 7800 | 720 | 84 | 6400 | 540 | 60 |
2001 | 9000 | 800 | 70 | 7200 | 850 | 75 | 8500 | 950 | 80 | 5700 | 485 | 60 | 4500 | 600 | 75 |
3.
In the year 1997, which state had the lowest percentage of candidates selected over the candidates appeared?
Answer: Option
Explanation:
The percentages of candidates selected over the candidates appeared in 1997, for various states are:
(i) For Delhi = | ![]() |
94 | x 100 | ![]() |
% = 1.175%. |
8000 |
(ii) For H.P. = | ![]() |
82 | x 100 | ![]() |
% = 1.051%. |
7800 |
(iii) For U.P. = | ![]() |
78 | x 100 | ![]() |
% = 1.040%. |
7500 |
(iv) For Punjab | ![]() |
85 | x 100 | ![]() |
% = 1.037%. |
8200 |
(v) For Haryana | ![]() |
75 | x 100 | ![]() |
% = 1.172%. |
6400 |
Clearly, this percentage is lowest for Punjab.
Discussion:
6 comments Page 1 of 1.
Akshay said:
6 years ago
1. Take 1% of every applied candidates and compare it with selected candidates.
2. If the difference between them is small or negative that's your answer.
3. But here the answer for UP and Punjab are the same (3) so you will have to calculate % for both of them (Its better than calculating for all of them).
2. If the difference between them is small or negative that's your answer.
3. But here the answer for UP and Punjab are the same (3) so you will have to calculate % for both of them (Its better than calculating for all of them).
(1)
VVK said:
9 years ago
2 and 3 steps like.
The difference between applied and qualified is 8, 115 as per 2 and 3 steps for lowest percentage the denominator must be higher than numerator so its 8200. So, the Answer Punjab.
The difference between applied and qualified is 8, 115 as per 2 and 3 steps for lowest percentage the denominator must be higher than numerator so its 8200. So, the Answer Punjab.
Kiran said:
10 years ago
Please explain in detail.
Prachi said:
1 decade ago
@Gopirotte.
Will you please explain this in detail? I didn't get your option 2 and 3.
Will you please explain this in detail? I didn't get your option 2 and 3.
Gopirotte said:
1 decade ago
1. Take difference of appeared and selected 8, 115.
2. For lowest percentage we consider lower differences with base as appeared candidates (8200).
3. Choose large no in denominator from options to get lowest %.
Therefor Punjab is our answer.
2. For lowest percentage we consider lower differences with base as appeared candidates (8200).
3. Choose large no in denominator from options to get lowest %.
Therefor Punjab is our answer.
MEENAKSHI said:
1 decade ago
Is there any short method to do this because in competitive exam there is very short time for calculation?
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