Data Interpretation - Table Charts - Discussion
Discussion Forum : Table Charts - Table Chart 2 (Q.No. 6)
Directions to Solve
Study the following table and answer the questions.
Number of Candidates Appeared and Qualified in a Competitive Examination from Different States Over the Years.
| State | Year | |||||||||
| 1997 | 1998 | 1999 | 2000 | 2001 | ||||||
| App. | Qual. | App. | Qual. | App. | Qual. | App. | Qual. | App. | Qual. | |
| M | 5200 | 720 | 8500 | 980 | 7400 | 850 | 6800 | 775 | 9500 | 1125 |
| N | 7500 | 840 | 9200 | 1050 | 8450 | 920 | 9200 | 980 | 8800 | 1020 |
| P | 6400 | 780 | 8800 | 1020 | 7800 | 890 | 8750 | 1010 | 9750 | 1250 |
| Q | 8100 | 950 | 9500 | 1240 | 8700 | 980 | 9700 | 1200 | 8950 | 995 |
| R | 7800 | 870 | 7600 | 940 | 9800 | 1350 | 7600 | 945 | 7990 | 885 |
6.
Combining the states P and Q together in 1998, what is the percentage of the candidates qualified to that of the candidate appeared?
Answer: Option
Explanation:
| Required percentage |
|
|||||||
|
||||||||
| = 12.35%. |
![]](/_files/images/data-interpretation/common/15-sym-cbracket-h1.gif)
Discussion:
7 comments Page 1 of 1.
Nizwa said:
7 years ago
2260=2000.
18300=18000,
2000/18000*100,
It gives me 11.11.
Am I correct? Please clarify me.
18300=18000,
2000/18000*100,
It gives me 11.11.
Am I correct? Please clarify me.
(2)
Akhilesh mishra said:
9 years ago
Divide and round off to the nearest 5 or 0 digit to solve fast.
2260 / 18300 = 226/1830,
Round off 225 / 1830 = 45 / 366,
Again round off 45/3660 = 9/73,
Again roundoff 9/70 * 100 = 12.1 answer ie close to 12.1, i.e. 12.35.
2260 / 18300 = 226/1830,
Round off 225 / 1830 = 45 / 366,
Again round off 45/3660 = 9/73,
Again roundoff 9/70 * 100 = 12.1 answer ie close to 12.1, i.e. 12.35.
(1)
Anand Singh said:
7 years ago
Nice answer, Thanks all.
(1)
Ror 13 said:
4 years ago
Easiest Way;
First sum both = 18300 and 2260 ---> 1830 & 226.
10 % = 183.
1% = 18.3.
Require + 10 % = 226 - 183 = 43;
1% = 18.3 == 20.
2% = 40 approx.
so 12% > approx.
But not 13 % as 1 % == 20,
and .5 % == 10.
First sum both = 18300 and 2260 ---> 1830 & 226.
10 % = 183.
1% = 18.3.
Require + 10 % = 226 - 183 = 43;
1% = 18.3 == 20.
2% = 40 approx.
so 12% > approx.
But not 13 % as 1 % == 20,
and .5 % == 10.
(1)
K.ramakrishnan said:
1 decade ago
Easy way to divide shortcut
Reet said:
1 decade ago
What is the easy way to divide shortcut? I can come to the second step but after that, help me please.
Alex hales said:
6 years ago
First, how to calculate the average and percentages of this given data?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers