Data Interpretation - Line Charts - Discussion
Discussion Forum : Line Charts - Line Chart 10 (Q.No. 3)
Directions to Solve
In a school the periodical examination are held every second month. In a session during April 2001 - March 2002, a student of Class IX appeared for each of the periodical exams. The aggregate marks obtained by him in each perodical exam are represented in the line-graph given below.
Marks Obtained by student in Six Periodical Held in Every Two Months During the Year in the Session 2001 - 2002.
Maximum Total Marks in each Periodical Exam = 500
3.
What is the percentage of marks obtained by the student in the periodical exams of August, 01 and Oct, 01 taken together ?
Answer: Option
Explanation:
| Required percentage = |  |
(370 + 385) | x 100 | ![]](/_files/images/data-interpretation/common/15-sym-cbracket-h1.gif) |
% = |  |
755 | x 100 |  |
% = 75.5%. |
| (500 + 500) | 1000 |
Discussion:
5 comments Page 1 of 1.
Kanishka jain said:
4 years ago
Anyone, please clarify this statement in detail.
Nidhirvyay said:
4 years ago
How come 500 + 500? Explain me.
(1)
Sayak Halder said:
6 years ago
How come 500+500?
SOWMIYA said:
1 decade ago
1000 Comes, Because Maximum Total Marks in each Periodical Exam = 500.
(1)
Obi said:
1 decade ago
Where is the 1000 coming from please I need answer?
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