Data Interpretation - Line Charts - Discussion

In a school the periodical examination are held every second month. In a session during April 2001 - March 2002, a student of Class IX appeared for each of the periodical exams. The aggregate marks obtained by him in each perodical exam are represented in the line-graph given below.

Marks Obtained by student in Six Periodical Held in Every Two Months During the Year in the Session 2001 - 2002.

Maximum Total Marks in each Periodical Exam = 500

4. 

What are the average marks obtained by the student in all the periodical exams during the last session ?

[A]. 373
[B]. 379
[C]. 381
[D]. 385

Answer: Option C

Explanation:

Average marks obtained in all the periodical exams

    = 1 x [360 + 365 + 370 + 385 + 400 + 405] = 380.83 ~= 381.
6


Vatshal said: (Aug 15, 2017)  
The Last session means previous year, so why is feb02 included in it?

Pema said: (Aug 2, 2018)  
Why dividing by 6 instead of average Mark 500? anyone help me to know the reason.

Pema said: (Aug 2, 2018)  
Why dividing by 6 instead of average Mark 500? anyone help me to know the reason.

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