# Data Interpretation - Line Charts - Discussion

### Discussion :: Line Charts - Line Chart 10 (Q.No.4)

In a school the periodical examination are held every second month. In a session during April 2001 - March 2002, a student of Class IX appeared for each of the periodical exams. The aggregate marks obtained by him in each perodical exam are represented in the line-graph given below.

Marks Obtained by student in Six Periodical Held in Every Two Months During the Year in the Session 2001 - 2002.

Maximum Total Marks in each Periodical Exam = 500

4.

What are the average marks obtained by the student in all the periodical exams during the last session ?

 [A]. 373 [B]. 379 [C]. 381 [D]. 385

Explanation:

Average marks obtained in all the periodical exams

 = 1 x [360 + 365 + 370 + 385 + 400 + 405] = 380.83 381. 6

 Vatshal said: (Aug 15, 2017) The Last session means previous year, so why is feb02 included in it?

 Pema said: (Aug 2, 2018) Why dividing by 6 instead of average Mark 500? anyone help me to know the reason.

 Pema said: (Aug 2, 2018) Why dividing by 6 instead of average Mark 500? anyone help me to know the reason.

 Samil said: (Feb 23, 2022) Why divide 1 by 6 at first? Shouldn't we compute directly with 6/ (Sum of All). I'm so confused, Anyone, please clarify this.