Data Interpretation - Line Charts - Discussion

Discussion Forum : Line Charts - Line Chart 8 (Q.No. 4)
Directions to Solve

Two different finance companies declare fixed annual rate of interest on the amounts invested with them by investors. The rate of interest offered by these companies may differ from year to year depending on the variation in the economy of the country and the banks rate of interest. The annual rate of interest offered by the two Companies P and Q over the years are shown by the line graph provided below.

Annual Rate of Interest Offered by Two Finance Companies Over the Years.


4.
An investor invested a sum of Rs. 12 lakhs in Company P in 1998. The total amount received after one year was re-invested in the same Company for one more year. The total appreciation received by the investor on his investment was?
Rs. 2,96,200
Rs. 2,42,200
Rs. 2,25,600
Rs. 2,16,000
Answer: Option
Explanation:

Amount received from Company P after one year (i.e., in 199) on investing Rs. 12 lakhs in it

= Rs. [12 + (8% of 12)] lakhs

= Rs. 12.96 lakhs.

Amount received from Company P after one year on investing Rs. 12.96 lakhs in the year 1999

= Rs. [12.96 + (10% of 12.96)] lakhs

= Rs. 14.256.

Appreciation received on investment during the period of two years

= Rs. (14.256 - 12) lakhs

= Rs. 2.256 lakhs

= Rs. 2,25,600.

Discussion:
12 comments Page 1 of 2.

SOURB said:   1 decade ago
How is this possible.

Why 8% in first step turned into 10% in next step?

Can you please elaborate it.
(1)

Akhila said:   1 decade ago
In the 1st step, we consider the interest rate of year 1998 and in the next step we consider the interest rate of the next year i.e.10%

Chip said:   1 decade ago
I got this wrong the first time around because I did not add the interest from the first year to the principal for the second year.

Annie said:   1 decade ago
I did not understand the last step i.e appreciation received on investment during the period of two years:

= Rs. (14.256 - 12) lakhs please explain.

Pratik said:   9 years ago
Initial = 1200000, interest in year 1998 = 0.08,
So interest amount received = 96000 (= 1200000 * 0.08) .
Net amount after investment = 1296000 (=1200000 + 96000) .

Next year 1999, interest rate = 0.1,
Amount invested = 1296000,
Interest received = 1296000 * 0.1= 129600.

Total interest (appreciation) = interest in (1998 + 1999) = 96000 + 129600 = 225600 => Answer.
(1)

Ravisha said:   9 years ago
Thank you all for the explanation.

Hemjit said:   9 years ago
An easier way:

Net interest rate: 8+10+(8*10/100) = 18.8% -- this would be the combined interest for two years.

Interest or appreciation: 12 * 18.8/100 = 225.6/100 = 2.256.
(2)

Sheena said:   9 years ago
Thanks for the explanation @Pratik.
(1)

Yagnas said:   7 years ago
Instead of appreciation, here interest would be the correct word.
(1)

Moin Khan Mondal said:   6 years ago
Total amount =p(1+R1/100)(1+R2/100)=1200000(1+8/100)(1+10/100)=1425600.

The answer is = 1425600-1200000 = 225600.
(1)


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