Data Interpretation - Bar Charts - Discussion
Discussion Forum : Bar Charts - Bar Chart 1 (Q.No. 5)
Directions to Solve
The bar graph given below shows the sales of books (in thousand number) from six branches of a publishing company during two consecutive years 2000 and 2001.
Sales of Books (in thousand numbers) from Six Branches - B1, B2, B3, B4, B5 and B6 of a publishing Company in 2000 and 2001.
5.
Total sales of branches B1, B3 and B5 together for both the years (in thousand numbers) is?
Answer: Option
Explanation:
Total sales of branches B1, B3 and B5 for both the years (in thousand numbers)
= (80 + 105) + (95 + 110) + (75 + 95)
= 560.
Discussion:
11 comments Page 1 of 2.
Cynthia said:
3 years ago
B1(80+105) + B2(95+110) + B5(75+95),
B1=185 B3=205 B5=170
185 + 205 + 170,
= 560.
B1=185 B3=205 B5=170
185 + 205 + 170,
= 560.
(2)
Faisal said:
4 years ago
560, if we add all the sales both 2000 and 2001 that is;
80 + 105 + 95 + 10 + 75 + 95 = 560.
80 + 105 + 95 + 10 + 75 + 95 = 560.
(1)
Ajay Godghase said:
8 years ago
Simple method addition of B1 B2 B3 ie the 185 + 205 + 170 = 560.
Shubhamg31291 said:
8 years ago
Please, Tell me the easiest way to solve the questions.
Ramesh said:
8 years ago
The answer is wrong its 530 not 560.
(1)
Lalith said:
8 years ago
I understand the solution. Thanks.
Aju said:
7 years ago
What is meant by thousands number?
Deni said:
3 years ago
How? Please explain in detail.
(1)
Indhupriya said:
4 months ago
Nice, good. Thanks @Cynthia.
Girish said:
9 years ago
Correct way to solve.
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