C++ Programming - References - Discussion
Discussion Forum : References - Programs (Q.No. 8)
8.
Which of the following statement is correct about the program given below?
#include<iostream.h>
int main()
{
int m = 2, n = 6;
int &x = m;
int &y = n;
m = x++;
x = m++;
n = y++;
y = n++;
cout<< m << " " << n;
return 0;
}Discussion:
5 comments Page 1 of 1.
J.sireesha said:
4 years ago
Here the values of x and m would be the same like m and n.
m=2 and n=6.
One thing remember in the program we use post increment operator
So, the first the actual value is assigned to the left hand variable.
For example;
a=5
b=a++;
Then b value =5 because we use post-increment.
Like in the same way;
Given values:
m=2,n=6
x=&m,y=&n;
Then x=2,y=6;
m=x++;
Then m=2
x=m++;
Then x=2
n=y++;
Then n=6
Y=n++;
Then y=6
So the final values of m=2 and n=6,
So, the option A is correct.
m=2 and n=6.
One thing remember in the program we use post increment operator
So, the first the actual value is assigned to the left hand variable.
For example;
a=5
b=a++;
Then b value =5 because we use post-increment.
Like in the same way;
Given values:
m=2,n=6
x=&m,y=&n;
Then x=2,y=6;
m=x++;
Then m=2
x=m++;
Then x=2
n=y++;
Then n=6
Y=n++;
Then y=6
So the final values of m=2 and n=6,
So, the option A is correct.
(2)
Legndery said:
9 years ago
This is clearly wrong.
m = x++;
Increments x, then returns the previous x. and assigns it to m.
So, x=x+1, but returns the old x. So the old x is assigned to m.
x = m++;
Same logic:
n = y++;
y = n++;
m = x++;
Increments x, then returns the previous x. and assigns it to m.
So, x=x+1, but returns the old x. So the old x is assigned to m.
x = m++;
Same logic:
n = y++;
y = n++;
Mohammad Mohsin seed said:
1 decade ago
Answers depend on compiler.
In DEV CPP it gives 2 6. While in turbo C++ it gives o/p 3 7.
In DEV CPP it gives 2 6. While in turbo C++ it gives o/p 3 7.
Simicivan173 said:
1 decade ago
This answer is only partially correct. (Depends on compiler!).
The result could be 2 6.
Because for example:
int x = 0; //initialize.
x = x++; //make copy of old version of x, increment x.
//assign old to x (lhs).
cout<<x; //prints 0 (not 1).
The result could be 2 6.
Because for example:
int x = 0; //initialize.
x = x++; //make copy of old version of x, increment x.
//assign old to x (lhs).
cout<<x; //prints 0 (not 1).
Amisha said:
1 decade ago
Here x = m.
And y = n are same.
First the m = x++ means m = x = 3 then x = m++.
So again m is increment by one so value is x = m = 4;
Same as for n and y operator so y = n = 8.
And y = n are same.
First the m = x++ means m = x = 3 then x = m++.
So again m is increment by one so value is x = m = 4;
Same as for n and y operator so y = n = 8.
(2)
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