C++ Programming - References - Discussion
Discussion Forum : References - Programs (Q.No. 14)
14.
What will be the output of the following program?
#include <iostream.h>
enum xyz
{
a, b, c
};
int main()
{
int x = a, y = b, z = c;
int &p = x, &q = y, &r = z;
p = z;
p = ++q;
q = ++p;
z = ++q + p++;
cout<< p << " " << q << " " << z;
return 0;
}Discussion:
10 comments Page 1 of 1.
Rajendra mahanor said:
1 decade ago
enum started value a=0, b=1, c=3 then,
Assign value x=a=0, y=b=1, z=c=2 then,
Reference value,
&p = x = 0.
&q = y = 1.
&r = z = 2.
Now p=z means p=2 again p=++q pre-increment &q=y=1, p=++q=2.
Then,
q = ++p = 3.
After q=4.
z = ++q+p++.
z = 3+4.
z = 7.
p = 4.
So output is p=4, q=4 and z=7.
Assign value x=a=0, y=b=1, z=c=2 then,
Reference value,
&p = x = 0.
&q = y = 1.
&r = z = 2.
Now p=z means p=2 again p=++q pre-increment &q=y=1, p=++q=2.
Then,
q = ++p = 3.
After q=4.
z = ++q+p++.
z = 3+4.
z = 7.
p = 4.
So output is p=4, q=4 and z=7.
(1)
Amarnath said:
1 decade ago
We can't change(++, --) enum values.
(1)
Sandesh said:
5 years ago
How q==4? Please anyone explain it.
(1)
Bidyut said:
8 years ago
How a, b, c are given values?
Pritha said:
8 years ago
How can we assign the values of a, b, c in such a random manner?
Abhinav said:
8 years ago
Explain it.
Manimegalai said:
7 years ago
Please, anybody explain it.
Vishal singh said:
7 years ago
It's the property of enum that they are initialized from 0 and stay in sequential increment order (i.e. A=0, b=1, c=2), also by enum property we can't change the value of enum after initialization.
Tavish said:
6 years ago
How can we random assigned the values to a b and c.
Minu said:
6 years ago
P=z=2.
P=++q=++1=2.
Q=++p=++2=3.
Z=++q+p++
Z=4+3=7.
Q=4.
P=3++=4.
P=++q=++1=2.
Q=++p=++2=3.
Z=++q+p++
Z=4+3=7.
Q=4.
P=3++=4.
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