C++ Programming - References - Discussion
Discussion Forum : References - Programs (Q.No. 4)
4.
Which of the following statement is correct about the program given below?
#include<iostream.h>
int main()
{
int x = 10;
int &y = x;
x = 25;
y = 50;
cout<< x << " " << --y;
return 0;
}Discussion:
13 comments Page 1 of 2.
Aakash said:
1 decade ago
Change in y will also b reflected in x. thats why x=y=50;
Then a decrement in y therefore in x too.
And answer is 49 49.
Then a decrement in y therefore in x too.
And answer is 49 49.
Sada said:
1 decade ago
How reflected?
Aayush said:
1 decade ago
Because there is & so it will act as an alias.
&y=x means that every change in x will be the same in y.
x and y will be the same :).
&y=x means that every change in x will be the same in y.
x and y will be the same :).
Vikas said:
10 years ago
Because here value of x is assigned in y. So every change in y also affect value of x.
Asaad said:
10 years ago
I can also add that x takes the value of y and also y takes the value of x. This appears when you put y=50;
And then x=25;
The output will become 24 24.
Just try it.
And then x=25;
The output will become 24 24.
Just try it.
Bhawna said:
10 years ago
If we create an integer variable and then create a reference which refers to this, any mention of the reference will be exactly the same as a mention to original variable.
Muhammad Mazhar said:
9 years ago
There is a confusion that the value of x is printed first, then -- decrement the value of y and print.
According to this, the value should be 50 49.
According to this, the value should be 50 49.
Meenakshi L said:
9 years ago
Is y = x same as &y=x?
As you said before the value of x is stored in y. So, we can use y=x is enough.
Why we need to use &y=x?
As you said before the value of x is stored in y. So, we can use y=x is enough.
Why we need to use &y=x?
Kjell said:
8 years ago
What compiler are you using?
I verified it with Apple LLVM 8.0 and g++ 5.4.0:
1. the result is 50 49,
2. #include <iostream.h> is not valid since a long time, it must be #include <iostream>
<< Is evaluated left to right, the decrement will happen after x was already streamed.
I verified it with Apple LLVM 8.0 and g++ 5.4.0:
1. the result is 50 49,
2. #include <iostream.h> is not valid since a long time, it must be #include <iostream>
<< Is evaluated left to right, the decrement will happen after x was already streamed.
Abhishek said:
5 years ago
Yes, I agree, The answer will be 50 49.
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