C++ Programming - References - Discussion
Discussion Forum : References - Programs (Q.No. 1)
1.
Which of the following statement is correct about the program given below?
#include<iostream.h>
int main()
{
int x = 80;
int y& = x;
x++;
cout << x << " " << --y;
return 0;
}Discussion:
20 comments Page 1 of 2.
Tanuja Ankush Gawade said:
1 year ago
#include<iostream.h>
int main()
{
int x = 80;
int y& = x;
x++;
cout << x << " " << --y;
return 0;
}
In the above program "using namespace std; "line or "std" library must be included and The "&" symbol must be placed before the variable name like int &y =x;
Hence there is an error.
int main()
{
int x = 80;
int y& = x;
x++;
cout << x << " " << --y;
return 0;
}
In the above program "using namespace std; "line or "std" library must be included and The "&" symbol must be placed before the variable name like int &y =x;
Hence there is an error.
Tauseef Sarwar said:
2 years ago
#include<iostream.h>
int main()
{
int x = 80;
int y& = x;
x++;
cout << x << " " << --y;
return 0;
}
@All.
This shows error, but when the ampersand symbol is written before y then the answer will be 81 80.
int main()
{
int x = 80;
int y& = x;
x++;
cout << x << " " << --y;
return 0;
}
@All.
This shows error, but when the ampersand symbol is written before y then the answer will be 81 80.
(1)
Anurag said:
5 years ago
Please note that &y is just creating a reference and reference is automatically deferred so --y is purely a valid operation.
So the answer is 81 80.
So the answer is 81 80.
(1)
R@j said:
7 years ago
#include <stdio.h>
int main()
{
int x=80;
int &y = x;
x++;
printf("Hello World %d %d ",x, --y);
return 0;
}
And the answer is 80 80.
int main()
{
int x=80;
int &y = x;
x++;
printf("Hello World %d %d ",x, --y);
return 0;
}
And the answer is 80 80.
(2)
Sarvesh karan said:
7 years ago
Why it is compile time error. It should take as bitwise & and then proceed.
Hatos said:
8 years ago
I got this error:
expected initializer before '&' token
int y& = x;
^
Code::Blocks
Release 17.12 rev 11256
g++.exe (GCC) 7.2.0
std = c++1z
Can anyone help me to resolve it?
expected initializer before '&' token
int y& = x;
^
Code::Blocks
Release 17.12 rev 11256
g++.exe (GCC) 7.2.0
std = c++1z
Can anyone help me to resolve it?
Vipul said:
8 years ago
cout << x << " " << --y.
This is processed right to left, starting with loading y, decrementing it and so on.
This is processed right to left, starting with loading y, decrementing it and so on.
Mohammad Taha said:
9 years ago
int y& is basically a reference variable, and reference variable is internally a constant pointer. And one cannot change constant pointer value. So, it's compile time error.
SAURABH SHARMA said:
9 years ago
It should be y=&x ;
OR
y=y & x;
Here & is BITWISE AND.
#include<iostream.h>
#include<conio.h>r
int main()
{
int x = 80,y=10;
clrscr();
y = y & x;
x++;
cout << x << " " << --y;
getch();
return 0;
}
output.
--------
64 32 16 8 4 2 1
x = 1 0 1 0 0 0 0
y = 0 0 0 1 0 1 0
--------------------------
y = 0 0 0 0 0 0 0
--y = -1.
OR
y=y & x;
Here & is BITWISE AND.
#include<iostream.h>
#include<conio.h>r
int main()
{
int x = 80,y=10;
clrscr();
y = y & x;
x++;
cout << x << " " << --y;
getch();
return 0;
}
output.
--------
64 32 16 8 4 2 1
x = 1 0 1 0 0 0 0
y = 0 0 0 1 0 1 0
--------------------------
y = 0 0 0 0 0 0 0
--y = -1.
Kevin said:
10 years ago
Position of '&' is incorrect.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers