C++ Programming - OOPS Concepts - Discussion

Two functions are overloaded if they have the same name but different arguments (parameter list).

Two parameter lists are different if :

1) They have a different number of arguments.
2) They have the same number of arguments but differ in the type of one argument at least.
3) They have the same number of arguments and data types but with a different order.

@Viranshukumar.

The example which you given is not correct since all arguments have the same type so the order is meaningless.

First, the arguments don't count here, only the parameters count.

Then, the order of the parameters doesn't count if their type is the same, so 'B' doesn't apply.

In case the types are different and their order is different, that means different parameters' types so this case is covered by 'A'.

C++ allows you to specify more than one definition for a function name or an operator in the same scope, which is called function overloading and operator overloading respectively.

Function overloading means using the same function to perform different tasks.

So the name will be same. But the data types and number of arguments may vary.

Function overload can have the same number of argument but different of different types. So I think the correct answer should be A, B, C.

Option B is not correct because :

int fun (int a, int b, int c)

Here I change the order or arguments.

int fun (int b, int c, int a)

In function overloading function has same name but accessing depends on the no. And type of arguments so, answer is option A & B.

int foo(int a,float b){ } and int foo(float a,int b){} are different.

This shows function arguments order difference.

Function overloading definition it contain same name but different datatype n return type n arguments list.

Overloading is nothing but same function with different arguments.