C++ Programming - Functions - Discussion
Discussion Forum : Functions - Programs (Q.No. 1)
1.
What will be the output of the following program?
#include<iostream.h>
long BixFunction(int x, int y = 5, float z = 5)
{
return(++x * ++y + (int)++z);
}
int main()
{
cout<< BixFunction(20, 10);
return 0;
}Discussion:
16 comments Page 1 of 2.
Srijan s said:
4 years ago
I think there will be an error as there are only two parameters passed where as in function definition we can clearly see there are 3 variables.
(1)
Gopi said:
5 years ago
Gives error.
use #include<iostream> instead #include<iostream.h>
use #include<iostream> instead #include<iostream.h>
Sindhu said:
8 years ago
What does the Bixfunction (20, 10) mean ?
If it indicates x=20, y=10, but y=5 was given in declaration ?
If it indicates x=20, y=10, but y=5 was given in declaration ?
(1)
Jaideep gupta said:
10 years ago
Ya I computed in the values written in main function overwritten the values present in bix function.
Patel Ravi said:
1 decade ago
Nice programming language.
Aish said:
1 decade ago
See in float z = 5.0 then in int z = 5 we can take like this. I am right?
(1)
Archana said:
1 decade ago
There are two data types for variable z. How it is possible?
Can anyone explain?
Can anyone explain?
Vinay said:
1 decade ago
Why not error?
Ameet said:
1 decade ago
x and y always refer the current value passed into 2nd fun so x will become 20 and y become 10. Whenever the pointer goes into the return that time x will become 21 and y will be 11 and z will be 6.21*11+6=237 that is final answer.
(1)
Rajat Ravi said:
1 decade ago
Solution:
x = 20.
y = 10.
z = 5.
++x = 21.
++y = 11.
++z = 6.
21*11+6 = 237.
x = 20.
y = 10.
z = 5.
++x = 21.
++y = 11.
++z = 6.
21*11+6 = 237.
(6)
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