C++ Programming - Functions - Discussion

@All.

According to me, the Correct code to get IndiaBIX 8.

#include<iostream>
using namespace std;
#include<string.h>
#include<malloc.h>
class BixString
{
char txtName[20];
public:
BixString(char *txtTemp = NULL)
{
if(txtTemp != NULL)
strcpy(txtName, txtTemp);
}
void Display(void)
{
cout<<txtName;
}
};
int main()
{
char *txtName = (char*)malloc(10);
strcpy(txtName, "IndiaBIX");
//*txtName = 48;
BixString objTemp(txtName);
objTemp.Display();
cout<<" "<<sizeof(txtName);
return 0;
}

txtName = "IndiaBIX" which is of size 8.
then *txtName = 48 which modifies txtName as 0ndiaBIX.
which is again of size 8 so answer is 8.

The sizeof operator gives the total size occupied by the address. In this case, its 8. So it should be 8. The String would not be displayed as the Display function was never called.

@All.

The answer depends on the platform that we are running this program and is either 4 or 8 (the size of the pointer on x86 and x64 respectively). And there is no code to print the content of the string.

The main thing *txtName = 48; was replace the first char with 48 which means zero('0') now malloc allocate "0ndiaBIX" now size is 9.

According to me, The output is 4.

Here strlen return size of string as 8. But the string is followed by null character '\0' so size will be increased by 1 more bit, Finally, size becomes 8+1 = 9.

That's why output is IndiaBix 9.

The correct answer is 4 size of pointer.

The correct answer will be 4 which is size of int, so it is option C.

How indiabix will be printed? They are not calling display function.