C++ Programming - Functions - Discussion

In C++, when default arguments are specified in the function prototype, they do not need to be repeated in the function definition.

The default values specified in the prototype are automatically considered when the function is called, and they do not need to be redeclared in the function definition.

Therefore, the correct statement is The default arguments are given in the function prototype and do not need to be repeated in the function definition.

When a function prototype have default argument, then in function definition we do not need to again repeat it. Just look at the below programme.

#include<iostream.h>
void print(int ,int a=10); // function pro type
int main()
{ int b=11;
print(b);
return 0;
}
void print(int b ,int a) //void print(int b,int a=10) is wrong
{ cout<<"a ="<<a<<endl;
cout<<"b="<<b<<endl;
}

Prototype is used to tell the compiler that there is a function named this so if we call the function before function definition it is error so prototype is used to build function call not definition.

B is correct. The default arguments are given in the function prototype. You can not set default values in the definition of a function.

Compiler uses the prototype information to build a call, not the function definition.

Please elaborate.