C++ Programming - Functions - Discussion
Discussion Forum : Functions - Programs (Q.No. 21)
21.
What will be the output of the following program?
#include<iostream.h>
class IndiaBix
{
int K;
public:
void BixFunction(float, int , char);
void BixFunction(float, char, char);
};
int main()
{
IndiaBix objIB;
objIB.BixFunction(15.09, 'A', char('A' + 'A'));
return 0;
}
void IndiaBix::BixFunction(float, char y, char z)
{
K = int(z);
K = int(y);
K = y + z;
cout<< "K = " << K << endl;
}
Discussion:
14 comments Page 1 of 2.
AKS said:
1 decade ago
char('A'+'A') is 65+65=130 which is out the signed range of char i.e., -128 to 127
So, -128+(130-128)= -126 = z
Therefore,
K = y + z = 65 + -126 = -61
So, -128+(130-128)= -126 = z
Therefore,
K = y + z = 65 + -126 = -61
(4)
Arpan said:
5 years ago
K is initialized within a class without access specifier, so by default it will be private. How they are able to use K outside the class?
(1)
Rakesh said:
1 decade ago
How this work please explain me?
Shiksha said:
1 decade ago
A single definition for two declarations isn't an issue here!
Why so?
Why so?
Anonymous said:
1 decade ago
Yes no issue.
If there would be a function call to the function which is only declared but not defined, then while checking the compiler would have been given a compile time error that the function is not defined.
And by the way here there is not a single definition for two declarations, rather the definition is specified only for the one function i.e.
void BixFunction(float, char, char);
If there would be a function call to the function which is only declared but not defined, then while checking the compiler would have been given a compile time error that the function is not defined.
And by the way here there is not a single definition for two declarations, rather the definition is specified only for the one function i.e.
void BixFunction(float, char, char);
Sai theja said:
8 years ago
@Aks.
Why A value is taken as 65?
Why A value is taken as 65?
Nam said:
8 years ago
The char type can be both signed (from -128 to 127) or unsigned (0 to 255), it is depended on the concrete C++ implementation. So the answer -61 is not always true.
See "The C++ Programming Language, 4th edition" by Bjarne Stroustrup, section 6.2.3.
See "The C++ Programming Language, 4th edition" by Bjarne Stroustrup, section 6.2.3.
Anonymous said:
8 years ago
There is no variable name for float in member function definition.
Anonymous said:
8 years ago
This is BS question! Why you are supposed to remember ASCII table and exact value of signed char?
Max said:
8 years ago
@ALL.
cout<< "K = " << K << endl; so it will 100% print "K = ", wtf is answer "M = "?
cout<< "K = " << K << endl; so it will 100% print "K = ", wtf is answer "M = "?
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