C++ Programming - Constructors and Destructors - Discussion

Discussion Forum : Constructors and Destructors - Programs (Q.No. 3)
3.
Which of the following statement is correct about the program given below?
#include<iostream.h> 
class Bix
{
      int x; 
    public:
      Bix();
     ~Bix();
      void Show() const;
};
Bix::Bix()
{
    x = 25;
}
void Bix::Show() const
{
    cout<< x;
}
int main()
{
    Bix objB;
    objB.Show();
    return 0; 
}
The program will print the output 25.
The program will print the output Garbage-value.
The program will report compile time error.
The program will report runtime error.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
19 comments Page 1 of 2.

Jenny said:   6 years ago
First of all, it should be <iostream>
And next would be ~Bix(); as ~Bix(){};

Raghavendra said:   6 years ago
It's because of cout it should be std::cout and include file should be iostream not iostream.h.

Priya modak said:   7 years ago
It is because of undefined reference to the destructor.

write ~Bix(); as ~Bix(){};
Then it will work.

Neha said:   7 years ago
program throw runtime error =Bix::~Bix(void)" not compile time.

Please help me to solve this.

Niketa Agarwal said:   9 years ago
It is because of undefined reference to destructor.

write ~Bix(); as ~Bix(){};
Then it will work.
(1)

Vigneshwar said:   9 years ago
Const function does not allow the object members to be modified. In this program, we are not modifying so it will print the output 25.

Jayanthi Akula said:   10 years ago
When we are calling any constant function. The object of that function should be constant. Here in program "objB" is the object of "Bix" which is having a normal object.

So a normal object can not call its constant function. Try the program by declaring the object as "const" like const Bix objB.

Guriya said:   1 decade ago
Yes, runtime error: undefined symbol Bix::~Bix().

Sid said:   1 decade ago
Yes its run time error. So answer is D.

Swetha said:   1 decade ago
The program get compiled and it provides only run time error.


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