Computer Science - Networking - Discussion
Discussion Forum : Networking - Section 3 (Q.No. 35)
35.
You have a network ID of 192.168.10.0 and require at least 25 host IDs for each subnet, with the largest amount of subnets available. Which subnet mask should you assign?
Discussion:
6 comments Page 1 of 1.
Wasim sajjad said:
4 years ago
@Manish
128+64+32= 224.not 242. Please check.
128+64+32= 224.not 242. Please check.
Manish said:
6 years ago
It's class C.
So in HID, we have 8bit.
5bit for host remains 3 then 128+64+32= 242.
255.255.255.242.
So in HID, we have 8bit.
5bit for host remains 3 then 128+64+32= 242.
255.255.255.242.
Bobby said:
8 years ago
D is the right answer.
Junip said:
9 years ago
I agree with the given answer i.e option B.
Sehal said:
1 decade ago
D is the right answer because we need 5 bits for 25 host IDs. So we will pick first five bits from left which will be like this.
128+64+32+16+8 = 248. So D is right option.
128+64+32+16+8 = 248. So D is right option.
Sateesh said:
1 decade ago
It requires 25 host IDs in class C.
dec(25) = bin(11001) total 5 bits required.
In last part there are 8 bits.
11111111 = 255 ---> but we need 5 bits for 25 host IDs.
So, 11100000 = 224.
So the subnet mask is 255.255.255.224.
dec(25) = bin(11001) total 5 bits required.
In last part there are 8 bits.
11111111 = 255 ---> but we need 5 bits for 25 host IDs.
So, 11100000 = 224.
So the subnet mask is 255.255.255.224.
(1)
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