Discussion :: Networking - Section 8 (Q.No.27)
|Raj Gopal said: (Aug 24, 2015)|
|A is right answer since three bits are borrowed (128+64+32) = 224.|
|Shewangizaw Bogale said: (Jan 5, 2017)|
|Yes, A is the Only correct Answer.|
|Shewangizaw Bogale said: (Feb 18, 2017)|
|8 subnets, 8 = 2 ^3, so the network bits(N) is = 3, so the subnet mask is = 11100000 in binary and 224 in decimal notation.
So, the correct Answer is A . 255.255.224.0.
|Iglooroy said: (Apr 20, 2017)|
|The correct Answer is A.|
|Sandeep Singh said: (Apr 22, 2017)|
|2^n-2= subnet for eight we need 4 bits i think but 255.255.
255.255.240 is the answer.
|Obaid said: (Sep 13, 2018)|
2^n-2 is the formula of valid hosts not for the subnet, so n=3 is correct and A is a valid answer.
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