Computer Science - Networking - Discussion
Discussion Forum : Networking - Section 2 (Q.No. 29)
29.
If delays are recorded as 10 bit numbers in a 50 router network, and delay vectors are exchanged twice a second, how much bandwidth per fill duplex line is occupied by the distributed routing algorithm?
Discussion:
3 comments Page 1 of 1.
ANINDYA said:
1 decade ago
50*2*10 = 1000
Ravi kumar said:
1 decade ago
Delay bit by all router=10*50= 500 bit.
Here given delay vector are exchanged twice a second, it means one bit exchanged in 2 sec. So 500 bit will exchanged in 500*2= 1000 bit.
Here notice that 500 bit cover by all router in only one second. Hence 1000 bps.
Here given delay vector are exchanged twice a second, it means one bit exchanged in 2 sec. So 500 bit will exchanged in 500*2= 1000 bit.
Here notice that 500 bit cover by all router in only one second. Hence 1000 bps.
(1)
Kirti said:
9 years ago
Not one bit in 2 sec, 2 bits in one sec is correct and moreover in 1 sec 50 * 2 * 10 = 1000 is correct.
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