Computer Science - Networking - Discussion
Discussion Forum : Networking - Section 7 (Q.No. 29)
29.
Phase shift keying (psk) method is used to modulate digital signals at 9600 bps using 16 levels. Find the line signaling speed (i.e., modulation rate)
Discussion:
3 comments Page 1 of 1.
Anindita Das said:
1 decade ago
MODULATION BAUD RATE BIT RATE
4-PSK N 2N
8-PSK N 3N
16-PSK N 4N
Two values are provided. One is bps which is nothing but Bits per second which is 9600 and also level which is 16. According to the table given above, for a 16-PSK, given the baud rate N, the bit rate would be 4N. Here bps is provides which is 9600. In order to calculate the baud rate we have to divide bps/4, because the signal level is 16. So the answer would be 9600/4=2400 baud. That is how the answer is arrived at.
4-PSK N 2N
8-PSK N 3N
16-PSK N 4N
Two values are provided. One is bps which is nothing but Bits per second which is 9600 and also level which is 16. According to the table given above, for a 16-PSK, given the baud rate N, the bit rate would be 4N. Here bps is provides which is 9600. In order to calculate the baud rate we have to divide bps/4, because the signal level is 16. So the answer would be 9600/4=2400 baud. That is how the answer is arrived at.
Mrs. Aparna Joshi said:
8 years ago
2pow4= 16, so we have to take 4 bits of 16 levels.
Here,
Baud rate = 9600 bps
Bit rate = 4 bits
Modulation rate = baud rate / bit rate.
So, Modulation rate = 9600 bps/4 bits = 2400 bands.
Here,
Baud rate = 9600 bps
Bit rate = 4 bits
Modulation rate = baud rate / bit rate.
So, Modulation rate = 9600 bps/4 bits = 2400 bands.
Nithin T said:
9 years ago
Can anyone please elaborate this?
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