Computer Science - Networking - Discussion
Discussion Forum : Networking - Section 2 (Q.No. 9)
9.
Four routers have to be interconnected in a point-to-point Network. Each pair of root us may connected by a high-speed line, a medium speed line or a low speed line. Find the total number of topologies.
Discussion:
17 comments Page 1 of 2.
Pushpendra Kuntal said:
1 decade ago
There are four routers A, B, C, D, so point to point connections are AB, AC, AD, BC, BD, CD(means there are 6 point to point connection).
And each connection may have either high speed line, medium speed line or low speed line, so we can say there are 3 possibilities of above each 6 point to point connections,
So 3^6= 729 so that is correct answer. :).
And each connection may have either high speed line, medium speed line or low speed line, so we can say there are 3 possibilities of above each 6 point to point connections,
So 3^6= 729 so that is correct answer. :).
(5)
Rasheed Khan said:
8 years ago
Just use simple Formula n(n-1)/2.
As we know that there are 4 routers so put values in above formula.
4(4-1)/2 = 6 :-which means that there will be 6 point to point channels and (4-1) which is 3 will denote maximum number of point to point connection each router could have.
So, finnally 3^6 = 729.
As we know that there are 4 routers so put values in above formula.
4(4-1)/2 = 6 :-which means that there will be 6 point to point channels and (4-1) which is 3 will denote maximum number of point to point connection each router could have.
So, finnally 3^6 = 729.
(5)
Ayan said:
1 decade ago
There will be 6 point to point channels among 4 routers and max no of line is 3 . So the solution is 3^6 .
SADIQ said:
9 years ago
Nice explanation, Thanks @Pushpendra.
It helps me to understand this difficult question.
It helps me to understand this difficult question.
Abc said:
1 decade ago
@Pushpendra. Your answer is quite easy to understand. Thank you.
Buganda said:
8 years ago
@Pushpendra Kuntal.
Thank you a lot for opening my mind.
Thank you a lot for opening my mind.
Vimy sarcar said:
1 decade ago
=(4-Main Modem)^8-(uplink+Downlink).
=(4-1)^(8-2).
729.
=(4-1)^(8-2).
729.
Bob said:
1 decade ago
Can anybody give a solution for the above problem?
Husnain gilani said:
8 years ago
You are the best, thanks a lot @Pushpendra.
Shweta said:
9 years ago
Thanks @Pushpendra:). Nice explanation:).
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