Computer Science - Networking - Discussion
Discussion Forum : Networking - Section 4 (Q.No. 5)
5.
Four bits are used for packet sequence numbering in a sliding window protocol used in a computer network. What is the maximum window size?
Discussion:
7 comments Page 1 of 1.
Rajesh Kumar said:
8 months ago
If there were 8 bits then it would be (2^8-1).
So, 256-1=255 is the maximum window size.
Am I right?
So, 256-1=255 is the maximum window size.
Am I right?
Shewangizaw Bogale said:
9 years ago
Well explained, Thank you @Shruti Jain.
Shruti Jain said:
1 decade ago
For k-bit numbering scheme, the total number of frames, N, in the sliding.
Window can be given as follows (using modulo-k).
N = 2^k-1.
Hence the range of sequence numbers is: 0, 1, 2, and 3.
Hence when a 4 bit numbering scheme is used the window size.
N = 2^4-1 = 15.
Window can be given as follows (using modulo-k).
N = 2^k-1.
Hence the range of sequence numbers is: 0, 1, 2, and 3.
Hence when a 4 bit numbering scheme is used the window size.
N = 2^4-1 = 15.
Preetinder kaur said:
1 decade ago
No formula is (2^ n)-1 i.e. (2^ 4)-1) = 16-1 = 15.
Datta vamshi said:
1 decade ago
Which one is correct?
Rohini said:
1 decade ago
But if we use selective repeat then it will be 2^ (n-1) i.e. 8.
Kamlesh said:
1 decade ago
The correct ans is c : sliding window protocol having window (2^n-1).
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers