Computer Science - Networking - Discussion
Discussion Forum : Networking - Section 8 (Q.No. 48)
48.
A 2000-character text file has to be transmitted by using a 1,200 baud modem. Can you tell how long will it take?
Discussion:
4 comments Page 1 of 1.
Amit said:
6 years ago
1 Character = 8 bits.
1 Baud = 1 bit/sec.
A frame = Start Bit + Data Bit + Parity Bit + Stop Bit.
= 1+8+1+2=12 bit.
Time for transmission = (12*2000)/1200 = 20 seconds.
Correct answer is option B.
1 Baud = 1 bit/sec.
A frame = Start Bit + Data Bit + Parity Bit + Stop Bit.
= 1+8+1+2=12 bit.
Time for transmission = (12*2000)/1200 = 20 seconds.
Correct answer is option B.
(1)
Taiyaba said:
8 years ago
1200/12=100 by steps.
Therefore 2000*1byte/100byteps=20 second.
B is the correct answer.
Therefore 2000*1byte/100byteps=20 second.
B is the correct answer.
(1)
Shewangizaw Bogale said:
9 years ago
1 Baud = 1 bit per sec.
So, (16,000 bit * Sec) / 1200 bit = 160/12 = 13.333 Sec.
The Correct & final Answer is E. None.
So, (16,000 bit * Sec) / 1200 bit = 160/12 = 13.333 Sec.
The Correct & final Answer is E. None.
Raj gopal said:
1 decade ago
1 second ---- >1200 bits.
? ------ > 2000*8 bits.
I think the answer is 12 seconds.
? ------ > 2000*8 bits.
I think the answer is 12 seconds.
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