# Computer Science - Digital Computer Electronics - Discussion

### Discussion :: Digital Computer Electronics - Section 2 (Q.No.2)

2.

A microprocessor has memory locations from 0000 to 3FFF. Each memory location stores 1 byte. How bytes can the memory store? Express this in kilobytes?

 [A]. 4,095, 4K [B]. 16,384, 16K [C]. 32,740, 32K [D]. 46,040, 46K [E]. None of the above

Explanation:

No answer description available for this question.

 Ajit said: (Jan 24, 2012) Can anyone explain the method ?

 Richa said: (Feb 6, 2012) Please explain the method for the solution.

 Richa said: (Feb 6, 2012) Convert into decimal form : 3FFF --- gives 16383. add 1 for location 0000. => 163384

 Chandni said: (Jul 4, 2012) Convert 3fff into binary and then into decimal. Which gives 16383 and add 1 for 0000 location. So 16384is correct answer.

 Pandees said: (Feb 28, 2014) Answer is: Hex = 3fff. Decimal = 3x163+15x162+15x161+15x160 = 16383. Signed decimal = 16383. Binary = 11111111111111.

 Sachin Meshram said: (Jun 7, 2014) 3FFF binary is 0011 1111 1111 1111. (note:0011 1111 1111 =2^10=1KB (here 10 is last 10 binary bit)). In 3FFF their is total 14 binary bit. i.e. 2^4*2^10=2^4KB=16KB=16*1024=16384.

 Anjali said: (Sep 20, 2016) Thank you all for explaining it.