Computer Science - Digital Computer Electronics - Discussion

2. 

A microprocessor has memory locations from 0000 to 3FFF. Each memory location stores 1 byte. How bytes can the memory store? Express this in kilobytes?

[A]. 4,095, 4K
[B]. 16,384, 16K
[C]. 32,740, 32K
[D]. 46,040, 46K
[E]. None of the above

Answer: Option B

Explanation:

No answer description available for this question.

Ajit said: (Jan 24, 2012)  
Can anyone explain the method ?

Richa said: (Feb 6, 2012)  
Please explain the method for the solution.

Richa said: (Feb 6, 2012)  
Convert into decimal form : 3FFF --- gives 16383. add 1 for location 0000. => 163384

Chandni said: (Jul 4, 2012)  
Convert 3fff into binary and then into decimal. Which gives 16383 and add 1 for 0000 location. So 16384is correct answer.

Pandees said: (Feb 28, 2014)  
Answer is:

Hex = 3fff.
Decimal = 3x163+15x162+15x161+15x160 = 16383.
Signed decimal = 16383.
Binary = 11111111111111.

Sachin Meshram said: (Jun 7, 2014)  
3FFF binary is 0011 1111 1111 1111.

(note:0011 1111 1111 =2^10=1KB (here 10 is last 10 binary bit)).

In 3FFF their is total 14 binary bit.

i.e. 2^4*2^10=2^4KB=16KB=16*1024=16384.

Anjali said: (Sep 20, 2016)  
Thank you all for explaining it.

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