Computer Science - Computer Fundamentals - Discussion
Discussion Forum : Computer Fundamentals - Section 13 (Q.No. 32)
32.
What is the number of bits needed for an address in a 4 K memory?
Discussion:
1 comments Page 1 of 1.
Anamika said:
9 years ago
It is simple,
Number of bits needed for address in memory = 2^n.
2^n = 4K.
2^n = 4096.
n =12.
1K = 1024 = 2^10.
4K = 4096 = 2^12.
Number of bits needed for address in memory = 2^n.
2^n = 4K.
2^n = 4096.
n =12.
1K = 1024 = 2^10.
4K = 4096 = 2^12.
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