Civil Engineering - Water Supply Engineering - Discussion
Discussion Forum : Water Supply Engineering - Section 4 (Q.No. 39)
39.
If w is the weight of water per cubic metre, Q is the discharge in cubic metres per sec and H is the total head, the required water horse power of the pump, is
none of these.
Discussion:
9 comments Page 1 of 1.
Santosh Kumar said:
3 years ago
wQH/75 is only if we take w in terms of MASS per unit volume i.e in density units.
However according to ques. w here is in weight per cubic metre thus here correct answer will be wQH/735.
Thus option (e) is correct.
However according to ques. w here is in weight per cubic metre thus here correct answer will be wQH/735.
Thus option (e) is correct.
Rosie said:
4 years ago
No it Should be 75 instead of 15.
Pavan said:
5 years ago
Yeah, it's WQH/75.
Not 15.
Not 15.
Joe said:
6 years ago
Water horse power= w*Q*H/75.
Break horse power= w*Q*H/ efficiency.
Break horse power= w*Q*H/ efficiency.
Gubendhiran said:
8 years ago
Hers, H.P = (wQH)/(0.735*efficiency of pump).
MRINAL KANTI BISWAS said:
8 years ago
If
w = unit wt of water in KN/cum.
Q = Discharge in cum/sec.
H = total head.
Then, required H.P. = wQH/0.735.
w = unit wt of water in KN/cum.
Q = Discharge in cum/sec.
H = total head.
Then, required H.P. = wQH/0.735.
(1)
Farhan said:
8 years ago
Yes, it should be 75 in place of 15.
Sagar said:
8 years ago
Agree @Shahzeb.
It is Wqh/75.
It is Wqh/75.
Shahzeb said:
9 years ago
The correct formula is WQH/75.
Plese tell me if I'm wrong.
Plese tell me if I'm wrong.
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