Discussion :: Water Supply Engineering - Section 4 (Q.No.39)
|Shahzeb said: (Jun 2, 2016)|
|The correct formula is WQH/75.
Plese tell me if I'm wrong.
|Sagar said: (Feb 27, 2017)|
It is Wqh/75.
|Farhan said: (Oct 3, 2017)|
|Yes, it should be 75 in place of 15.|
|Mrinal Kanti Biswas said: (Nov 14, 2017)|
w = unit wt of water in KN/cum.
Q = Discharge in cum/sec.
H = total head.
Then, required H.P. = wQH/0.735.
|Gubendhiran said: (Jan 3, 2018)|
|Hers, H.P = (wQH)/(0.735*efficiency of pump).|
|Joe said: (Jan 25, 2020)|
|Water horse power= w*Q*H/75.
Break horse power= w*Q*H/ efficiency.
|Pavan said: (Apr 24, 2020)|
|Yeah, it's WQH/75.
|Rosie said: (Sep 30, 2021)|
|No it Should be 75 instead of 15.|
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