Civil Engineering - Water Supply Engineering - Discussion
Discussion Forum : Water Supply Engineering - Section 5 (Q.No. 13)
13.
If average volume of sediment deposits is one-tenth million cubic metres per year in a reservoir of total capacity 10 million cubic metres, the dead storage will be filled up, in
Discussion:
8 comments Page 1 of 1.
Rynjah said:
9 years ago
Avg volume of sediment = (1/10) * 10^6 cum/year.
Total volume of reservoir = 10 * 10^6 cum.
No of year to fill = (10 * 10^6)/((1/10) * 10^6) = 100 years.
But dead storage is one fourth (1/4) of total storage.
Therefore no of years to fill the dead storage = 100/4 = 25 years.
Total volume of reservoir = 10 * 10^6 cum.
No of year to fill = (10 * 10^6)/((1/10) * 10^6) = 100 years.
But dead storage is one fourth (1/4) of total storage.
Therefore no of years to fill the dead storage = 100/4 = 25 years.
(1)
Snehal Wankhede said:
9 years ago
Max sediment load = 2 * avg sediment deposit =2 * (1/10) * 10^6 = 2 * 10^5 cubic m/yr.
T = volume or capacity/loading rate.
= 200000/(10 * 10^6) = 50yr.
T = volume or capacity/loading rate.
= 200000/(10 * 10^6) = 50yr.
Mahesh sinh said:
4 years ago
Dead storage=1/4 of total capacity 10.
= 2.5 million cubic meters.
Deposition rate =1/10 per year.
Then silting year= 2.5/1/10= 2.5 * 10,
= 25 year.
= 2.5 million cubic meters.
Deposition rate =1/10 per year.
Then silting year= 2.5/1/10= 2.5 * 10,
= 25 year.
(4)
Shiv Sajjan said:
7 years ago
Dead storage will always be 25% of total capacity.
i.e. 2.5 million cubic metres.
And to get dead storage fill up 2.5/0.1 = 25 years.
i.e. 2.5 million cubic metres.
And to get dead storage fill up 2.5/0.1 = 25 years.
(1)
Rushi Chaudhar said:
5 years ago
1÷10 per year = 0.1.
10÷ 0.1= 100 years to full reservoir,
But dead storage is 1/4 of total capacity,
100/4 = 25 years.
10÷ 0.1= 100 years to full reservoir,
But dead storage is 1/4 of total capacity,
100/4 = 25 years.
Sagar said:
7 years ago
Please anybody can give a correct solution of this problem?
Student said:
9 years ago
Please give the clear solution.
Ankit said:
7 years ago
You are Right, Thanks @Shiv.
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