Civil Engineering - Water Supply Engineering - Discussion

41. 

The water level in an open well was depressed by pumping 2.5 m and recuperated 2.87 m in 3 hours and 50 minutes. The yield of the well per minute is

[A]. 0.0033
[B]. 0.0044
[C]. 0.0055
[D]. 0.0066

Answer: Option C

Explanation:

No answer description available for this question.

Deepali said: (Jun 19, 2015)  
Please solve.

Mdpawar said: (Dec 3, 2015)  
How to solve this problems?

Roy said: (Aug 8, 2017)  
K/A = yield = 2.3log(2.87/2.5)/230 =0.0055.

Gubendhiran said: (Dec 31, 2017)  
Yield=(2.3/T)*log(s1/s2),
T= time after the pumping is stopped=3.83hrs,
s1= depression head=2.5m,
s2= recuperation head=2.5-2.87=0.37m,
Y=(2.3/3.83)*log(2.5/0.37),
Y=0.49828 m2/hr,
Y=0.0083 m2/min.

Sukhesh S C said: (Jan 1, 2018)  
Can you explain it in detail?

Kajol said: (Aug 20, 2018)  
@Roy

could you please explain the solution clearly?

Anil said: (Jul 2, 2019)  
What is 230?

Hardik said: (Jan 6, 2020)  
@Anil.

3 hours = 180 minute +50 minute.
=230 minute.

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