# Civil Engineering - Water Supply Engineering - Discussion

### Discussion :: Water Supply Engineering - Section 2 (Q.No.41)

41.

The water level in an open well was depressed by pumping 2.5 m and recuperated 2.87 m in 3 hours and 50 minutes. The yield of the well per minute is

 [A]. 0.0033 [B]. 0.0044 [C]. 0.0055 [D]. 0.0066

Explanation:

No answer description available for this question.

 Deepali said: (Jun 19, 2015) Please solve.

 Mdpawar said: (Dec 3, 2015) How to solve this problems?

 Roy said: (Aug 8, 2017) K/A = yield = 2.3log(2.87/2.5)/230 =0.0055.

 Gubendhiran said: (Dec 31, 2017) Yield=(2.3/T)*log(s1/s2), T= time after the pumping is stopped=3.83hrs, s1= depression head=2.5m, s2= recuperation head=2.5-2.87=0.37m, Y=(2.3/3.83)*log(2.5/0.37), Y=0.49828 m2/hr, Y=0.0083 m2/min.

 Sukhesh S C said: (Jan 1, 2018) Can you explain it in detail?

 Kajol said: (Aug 20, 2018) @Roy could you please explain the solution clearly?

 Anil said: (Jul 2, 2019) What is 230?

 Hardik said: (Jan 6, 2020) @Anil. 3 hours = 180 minute +50 minute. =230 minute.