Civil Engineering - Water Resources Engineering - Discussion
Discussion Forum : Water Resources Engineering - Section 3 (Q.No. 39)
39.
An intense rain is falling at a uniform rate of 7.5 cm/hour for a period of 60 minutes on a basin whose areas is 500 hectares. If the average infiltration capacity during the entire rain period is assumed to be 1.5 cm/hr, the maximum run-off rate based on 10 minute peak percentage of 16% from distributing graph of the basin, is
Discussion:
6 comments Page 1 of 1.
Marwa said:
5 years ago
7.5-1.5 = 6cm/hr.
For period 60 min,
6cm/hr * (60/60)hr = 6cm = 0.06m.
Max runoff = (500*10000 *0.06)/(10min*60)sec.
= 500m^3/sec * 16% = 80 cumecs.
For period 60 min,
6cm/hr * (60/60)hr = 6cm = 0.06m.
Max runoff = (500*10000 *0.06)/(10min*60)sec.
= 500m^3/sec * 16% = 80 cumecs.
(1)
Chinmay said:
6 years ago
First of all rainfall falling intensity 7.5 cm / hr & inflitration capacity 1.5 cm/hr.
So, 7.5 - 1.5 = 6 cm / hr.
Now we have to calculate for 10 min only so 1cm for 10 mins.
Also, it is mentioned that 16% only so,
(1*500*16) / 100 = 80 cumecs.
So, 7.5 - 1.5 = 6 cm / hr.
Now we have to calculate for 10 min only so 1cm for 10 mins.
Also, it is mentioned that 16% only so,
(1*500*16) / 100 = 80 cumecs.
(2)
Jaymin said:
7 years ago
Explain please.
Vishves said:
8 years ago
Can anyone explain it. How is it possible?
Harsha said:
8 years ago
Can anyone explain it?
Joginder said:
10 years ago
Can you explain how?
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