Discussion :: Water Resources Engineering - Section 1 (Q.No.33)
| Murali Krishna said: (Jun 8, 2014) | |
| Why it is 4 hours is it standard or any calculation is there? | |
| Gopal Dev Sharma said: (Jul 4, 2014) | |
| I guess, over land time duration: = ( 0.885 *L^3 / h )^0.385. = ( 0.885 *20^3 / 193 ) ^ 0.385. = ( 36.68 ) ^ 0.385. = 4.002 ~ 4 hours. Note : I'm not sure If It Is correct ... Let me know if it is. |
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| Srinu said: (Oct 14, 2016) | |
| @Gopal. Is this formula correct& how did you get this? Are you sure? |
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| Mughal Saltanat said: (Dec 4, 2016) | |
| T = (0.885 L^3/H)^0.385 | |
| Subhadeep Mandal said: (May 24, 2017) | |
| This mathematical approach is based on Kirpich Equation (1940). Tc (in minute) =[ 0.01947*(L^0.77) * ((h/L)^-0.385)], h = 193 m, L = 20000 m, Tc = 238.29 min ~ 3.97 hr ( ~ 4 hr.). |
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| Akhilesh Yadav said: (Jun 9, 2017) | |
| Kirpich Time Of Concentration. Watershed Hydrology Equations Formula:- Time of concentration (tc)=.0078{(L^.77)/(S^.385)}. Where- S=193/20000=.00965. Travel length (L)= 20000meter = 65616.797900262 foot, Slope (S)= 0.00965. Time of concentration (tc)=.0078{(20000^.77)/(.00965^.385)}, Time of concentration (tc)= 238.31597891773minute, Time of concentration (tc)=3.97193298197hour. |
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| Vjay said: (Aug 21, 2020) | |
| I am not getting this, please anyone explain this in detail. | |
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