Civil Engineering - Water Resources Engineering - Discussion

Discussion Forum : Water Resources Engineering - Section 1 (Q.No. 33)
33.
From the Survey of India map, the distance of the critical point is 20 km and difference in elevation is 193 m. The over land flow time, is
2 hours
3 hours
2 hours and 30 minutes
3 hours and 30 minutes
4 hours.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
8 comments Page 1 of 1.

Chaithu said:   4 years ago
( 0.885 *L^3/h )^0.385.
= (0.885 *20^3 / 193 ) ^ 0.385.
= (36.68 ) ^ 0.385.
= 4.002 ~ 4 hours.
(3)

Vjay said:   5 years ago
I am not getting this, please anyone explain this in detail.

AKHILESH YADAV said:   8 years ago
Kirpich Time Of Concentration.

Watershed Hydrology Equations Formula:-

Time of concentration (tc)=.0078{(L^.77)/(S^.385)}.
Where- S=193/20000=.00965.
Travel length (L)= 20000meter = 65616.797900262 foot,
Slope (S)= 0.00965.
Time of concentration (tc)=.0078{(20000^.77)/(.00965^.385)},
Time of concentration (tc)= 238.31597891773minute,
Time of concentration (tc)=3.97193298197hour.
(1)

Subhadeep Mandal said:   8 years ago
This mathematical approach is based on Kirpich Equation (1940).

Tc (in minute) =[ 0.01947*(L^0.77) * ((h/L)^-0.385)],
h = 193 m,
L = 20000 m,
Tc = 238.29 min ~ 3.97 hr ( ~ 4 hr.).
(1)

Mughal saltanat said:   9 years ago
T = (0.885 L^3/H)^0.385
(1)

Srinu said:   9 years ago
@Gopal.

Is this formula correct& how did you get this? Are you sure?

Gopal Dev Sharma said:   1 decade ago
I guess, over land time duration:

= ( 0.885 *L^3 / h )^0.385.
= ( 0.885 *20^3 / 193 ) ^ 0.385.
= ( 36.68 ) ^ 0.385.
= 4.002 ~ 4 hours.

Note : I'm not sure If It Is correct ... Let me know if it is.

Murali krishna said:   1 decade ago
Why it is 4 hours is it standard or any calculation is there?

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