Civil Engineering - Water Resources Engineering - Discussion
Discussion Forum : Water Resources Engineering - Section 3 (Q.No. 23)
23.
The area enclosed by the adjacent isohyets of a catchment basin are shown under :
The average depth of annual precipitation in the catchment basin will be
The average depth of annual precipitation in the catchment basin will be
Discussion:
5 comments Page 1 of 1.
Balaji k yadav said:
9 years ago
Pa = {A1(P1 + P2)/2 + A2(P2 + P3)/2 + A3(P3 + P4)/2 + A4(P4 + P5)/2 + A5(P5 + P6)/2} / {A1 + A2 + A3 + A4 + A5} = 6.5.
Where A1, A2, .......is an area in Sq m and P1, P2, P3, .....are isohyets in cm.
Where A1, A2, .......is an area in Sq m and P1, P2, P3, .....are isohyets in cm.
(1)
STARLION said:
8 years ago
(1500*45+2500*55+3000*65+2000*75+1000*85)/(1500+2500+3000+2000+1000) = 63.5.
P1 40, P2=50,P3=60 ECT ....A1 =1500, A2 2500 AND SO ON.
P1 40, P2=50,P3=60 ECT ....A1 =1500, A2 2500 AND SO ON.
(1)
SOUMYA said:
5 years ago
Thanks for explaining.
(1)
Raaj said:
7 years ago
Thank you all for giving the explanation of the answer.
Satish yadav said:
6 years ago
Thanks for explaining it.
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