Civil Engineering - Waste Water Engineering - Discussion


The ratio of minimum hourly flow to the average flow of sewage is

[A]. 1/4
[B]. 1/3
[C]. 1/2
[D]. 3/4

Answer: Option B


No answer description available for this question.

Arpit Shukla Ji said: (Apr 30, 2017)  
Min. Hourly flow =1/2 * avg flow.

Xyz said: (May 7, 2017)  
Maximum daily flow i= 2 Avg annual daily flow.
max hourly flow = 1.5 max daily flow=3 annual average daily flow.
Minimum daily flow=2/3 annual average daily flow.
Minimum hourly flow=1/2 minimum daily flow=1/3 annual average daily flow.
So the answer is correct.

Har said: (Aug 18, 2017)  
Here average flow of sewage=annual average daily flow.

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