Civil Engineering - Waste Water Engineering - Discussion
Discussion Forum : Waste Water Engineering - Section 1 (Q.No. 19)
19.
When drainage to sewage ratio is 20, the peak dry weather flow is
Discussion:
10 comments Page 1 of 1.
Gurjant singh said:
4 years ago
Thanks for explaining @Harsh Sharma.
Irfhan said:
5 years ago
Thanks @Harsh.
Harsh Sharma said:
6 years ago
Qd/Qs = 20.
Qd = 20 Is ---- (1).
In rainy weather;
Q = Qd+ Qs.
from eq (1)-
Q = 21 Qs ----- (2).
In peak dry weather;
Q= Qd + Qs (here Qd = 0 since no storm water).
Hence,
Q= Is ----- (3).
From ek (2) & (3).
Dry weather condition/ Rainy weather condition = (Qs/ 21Qs)*100 = 4.76...
Therefore, the peak dry weather flow is slightly less than 5% of the design discharge.
Qd = 20 Is ---- (1).
In rainy weather;
Q = Qd+ Qs.
from eq (1)-
Q = 21 Qs ----- (2).
In peak dry weather;
Q= Qd + Qs (here Qd = 0 since no storm water).
Hence,
Q= Is ----- (3).
From ek (2) & (3).
Dry weather condition/ Rainy weather condition = (Qs/ 21Qs)*100 = 4.76...
Therefore, the peak dry weather flow is slightly less than 5% of the design discharge.
(7)
Hdhjdje said:
6 years ago
@Rana, Nice explanation.
(1)
Khushwant rana said:
6 years ago
In dry weather only dry weather flow mean drainage flow will occur not the stormwater taken into account if drainage: sewage =1:20 then at dry flow only 1 unit will flow in a total of 21 unit mean % flow as compared to rainy season =1*100/21 = 4.76.
Er Mugundan R said:
7 years ago
Explain it, please.
Raj said:
7 years ago
Please explain it.
RAJESHKUMAR J said:
8 years ago
DWF = total supply of water * % of supply contributing to sewage, so when the ratio of drainage to sewage is high (20), then % of supply will be less, so DWF will be less than the design discharge.
Souvik Kundu said:
8 years ago
Please explain it.
Shreya said:
8 years ago
Anyone explain it please.
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