# Civil Engineering - Waste Water Engineering - Discussion

### Discussion :: Waste Water Engineering - Section 3 (Q.No.2)

2.

The moisture content of a sludge is reduced from 90% to 80% in a sludge digestion tank. The percentage decrease in the volume of sludge, is

 [A]. 25% [B]. 50% [C]. 10% [D]. 5%.

Explanation:

No answer description available for this question.

 Priyanka said: (Jun 4, 2015) Will you get me the explanation?

 Raihan said: (Jul 26, 2015) V2/V1 = (100-p1) / (100-p2) = 1/2.

 Vishal Shah said: (Jul 22, 2017) Initial = 90%. Final = 80%. V2/V1 = (100 - Initial) / (100- Final). = 100 - 90 / 100 - 80, = 10 / 20, = 1/2. For % multiply by 100. Ans is 50%.

 Kartik said: (Jun 22, 2019) Thank you @Vishal Shah.

 Abinash Das said: (Dec 13, 2019) The answer will be the same if the moisture content is reduced from 95% to 90%?? As per your explanation. V1/V2 = (100-Initial) / (100- Final) = 100-95 / 100-90 = 5/10 = 1/2. Is it right?

 Rabin Das said: (Feb 1, 2020) Thanks all.