Civil Engineering - Waste Water Engineering - Discussion

Discussion Forum : Waste Water Engineering - Section 7 (Q.No. 14)
14.
The rate of accumulation of sludge per person per year, is
10 litres
15 litres
20 litres
25 litres
30 litres.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
19 comments Page 1 of 2.

Naveed Ahmad said:   1 year ago
Sludge accumulation = 0.08 kg/person/ day.

Density of sludge = 1400 kg/m3.

Calculation:

Hence;

= 0.08 * 365 kg/person/day
= 29.2 kg / person / day

Density of sludge = 1400 kg/m3.
= 29.2 * (1000/1400).
Rate of accumulation of sludge = 20.85 litre/person/year.
= 20 liter/person/year.

Suhas said:   1 year ago
Sludge accumulation = 0.08 kg / person/day.
Density of sludge = 1400 kg/m3.

Calculation:

Hence

= 0.08 *365 kg/person/day.
= 29.2 kg / person/day.

Density of sludge = 1400 kg/m3.
= 29.2 * ( 1000/1400).

Rate of accumulation of sludge = 20.85 litre/person/year.
So, 20 liter/person/year.

MJM said:   2 years ago
I think the correct answer to be 30 ltrs.

SHUBHAM MEENA said:   2 years ago
I think 30 is the right answer.

Pavanc said:   3 years ago
Yes, the correct should be 30 Lit per year.

Suresh said:   4 years ago
In septic 30.

Sludge accumulation 80.

Narendra said:   5 years ago
Is code recommend the value of sludge per person in the year?

I think it is 30/lit/year.

Shivnandan kumar said:   5 years ago
Sludge accumulation =.08kg/person/day.
=.08*365kg/person/year
. =29.2kg/person/year
But answer says in litre.

Density of sludge=1400kg/m.m.m.
=29.2*(1000÷1400)
=20.85litre/person/year.

Since 1kg of sludge is not =1 lit of sludge.

Vipin said:   5 years ago
30 kg per person per years. Is same as 30 lit/person/years.
Because 0.08kg per person per day.

Msr said:   5 years ago
30 lit per person per year.


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