Civil Engineering - Waste Water Engineering - Discussion
Discussion Forum : Waste Water Engineering - Section 2 (Q.No. 2)
2.
If the depletion of oxygen is found to be 2.5 mg/litre after incubating 2.5 ml of sewage diluted to 250 ml for 5 days at 20°C, B.O.D. of the sewage is
Discussion:
11 comments Page 1 of 2.
Vikash said:
1 decade ago
BOD = DO X(DF).
2.5 X (250/2.5).
250mg/l.
2.5 X (250/2.5).
250mg/l.
Hem said:
10 years ago
DO and DF stands for?
Md Gulam Gos said:
9 years ago
DO: Dissolved Oxygen.
DF: Dilution Factor.
DF: Dilution Factor.
Yaregal t. said:
7 years ago
BOD =200 because don't forget 5 days.
Alvin A. said:
7 years ago
How did you get 200?
RAM PRASAD said:
6 years ago
That is BOD 5 days at 20° temperature.
Shweta said:
6 years ago
Answer is 250.
Swapnil Biraris said:
6 years ago
250 is the correct answer here.
(1)
Raisa Paul said:
5 years ago
D.F = sewage dilution/depletion of oxygen.
(1)
SHUBHAM SIDDHARTH NAYAK said:
5 years ago
BOD=(DO INITIAL-DO FINAL) * DF.
DO INITIAL - DO FINAL =2.5 mg/l (Given),
DF = (total volume of sewage and distilled water/volume of sewage sample)=250/2.5=100,
BOD = 2.5 * 100 = 250.
DO INITIAL - DO FINAL =2.5 mg/l (Given),
DF = (total volume of sewage and distilled water/volume of sewage sample)=250/2.5=100,
BOD = 2.5 * 100 = 250.
(2)
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