Civil Engineering - Waste Water Engineering - Discussion
Discussion Forum : Waste Water Engineering - Section 1 (Q.No. 10)
10.
The width of a rectangular sewer is twice its depth while discharging 1.5 m/sec. The width of the sewer is
Discussion:
30 comments Page 2 of 3.
Sahab said:
7 years ago
Let setling velocity = 1.0 m/sec.
Q = A.V (b=2h given)
A = Q/V.
b * (b/2) = 1.5/1.0,
B = 1.73m.
Q = A.V (b=2h given)
A = Q/V.
b * (b/2) = 1.5/1.0,
B = 1.73m.
Lupesh said:
7 years ago
Min velocity consider as 0.44m/sec.
Raaj said:
7 years ago
Thank you @Ramgopal Sahu and @Jay.
(1)
Jay said:
7 years ago
Here, Take velocity v = 0.45m/sec.
Ramgopal Sahu said:
8 years ago
Considering minimum velocity for effective flow I.e, 0.45m/sec.
A =Q/V => 1.5/0.45=3.333.
Area (A) => width b=2d , depth = d.
A= (2d)*d = 3.333.
d = 1.29m.
A =Q/V => 1.5/0.45=3.333.
Area (A) => width b=2d , depth = d.
A= (2d)*d = 3.333.
d = 1.29m.
(1)
Ankit said:
8 years ago
It is critical velocity case b=d/2.
Gopal lal kumawat said:
8 years ago
What is the typical slope of a waste pipe?
A. 4%, B.3%, C.2%, D.1%
A. 4%, B.3%, C.2%, D.1%
Lea said:
8 years ago
@Roy
Te answer is 1.76 because of 0.88x2=1.76.
Te answer is 1.76 because of 0.88x2=1.76.
SHAH NAWAZ KHAN said:
8 years ago
Kindly help me,
If ::h = 0.88 then by width= 2h, it becomes equal to = 1.76.
If ::h = 0.88 then by width= 2h, it becomes equal to = 1.76.
(1)
Roy said:
8 years ago
Assume velocity of flow as 1m/s given discharge Q= 1.5m3/s A=Q/V WIDTH=2HEIGHT, b *h=2h * h=2h^2=Q//v=1.5/1, h=0.88, W=1.36.
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