Civil Engineering - Waste Water Engineering - Discussion
Discussion Forum : Waste Water Engineering - Section 1 (Q.No. 6)
6.
If the diameter of sewer is 225 mm, the gradient required for generating self cleansing velocity, is
Discussion:
29 comments Page 1 of 3.
Sashank said:
5 years ago
Assume,
Self cleansing Velocity(V) = 0.9 m/s.
n=0.015,
and R=D/4.
then, V=1/n * (R)^(2/3) * (S)^(1/2).
On solving, S = 120.
Self cleansing Velocity(V) = 0.9 m/s.
n=0.015,
and R=D/4.
then, V=1/n * (R)^(2/3) * (S)^(1/2).
On solving, S = 120.
(18)
S Lakshmikanth said:
2 years ago
100mm = 1 in 60.
150mm = 1 in 100.
225mm = 1 in 120.
150mm = 1 in 100.
225mm = 1 in 120.
(9)
Sohail Khan said:
3 years ago
For 100 => 1 in 25.
For 150 => 1 in 65,
For 230 => 1 in 130.
For 150 => 1 in 65,
For 230 => 1 in 130.
(6)
Ujjwal mondal said:
7 years ago
Dia of sewer ------- Gradient ------ Velocity.
100 ------- 1 in 60 ------- 0.58 m/s.
150 ------- 1 in 100 ------- 0.61 m/s.
225 ------- 1 in 120 ------- 0.79 m/s.
100 ------- 1 in 60 ------- 0.58 m/s.
150 ------- 1 in 100 ------- 0.61 m/s.
225 ------- 1 in 120 ------- 0.79 m/s.
(6)
Shree said:
6 years ago
Thank you all for explaining the answer.
(2)
Pramit Samanta said:
5 years ago
Thank you @Gubendhiran.
(1)
Chaitu said:
6 years ago
Thank you @Ujjwal Mondal.
(1)
G D Mori said:
7 years ago
Good explanation @Ujjwal Mondal.
(1)
Amu bokato said:
7 years ago
Thank you @Ujjwal Mondal.
(1)
Robin said:
7 years ago
Take V = 0.9 m/s,
R = D/4,
then, S will be equal to 1/118 which is close to 1/120.
R = D/4,
then, S will be equal to 1/118 which is close to 1/120.
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