Civil Engineering - Waste Water Engineering - Discussion

Discussion Forum : Waste Water Engineering - Section 1 (Q.No. 27)
27.
A sewer pipe contains 1 mm sand particles of specific gravity 2.65 and 5 mm organic particles of specific gravity 1.2, the minimum velocity required for removing the sewerage, is
0.30 m/sec
0.35 m/sec
0.40 m/sec
0.45 m/sec
0.50 m/sec.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
16 comments Page 2 of 2.

Randos said:   7 years ago
Check the unit. @Sunil.

Pavani said:   7 years ago
According to me, it is 0.5.

Hemanth said:   7 years ago
@All

Here, s sand particle up to 1mm and organic particles up to 5mm, there is a condition for this one min velocity of 0.45 m/sec and Max 0.9m/sec.

Hence no need to calculate anything.
And @Neethu, the correct formula is;
Vs=√((8k/f)*(s-1)*g*d) this is the right one.
(5)

Nagdive said:   7 years ago
Thank you @Sunil And @Hemanth.

Masoom said:   6 years ago
Thank you @Sunil.

Ajay Kumar Yadav said:   2 years ago
0. 4m/s is the correct answer.
(1)


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