Civil Engineering - Waste Water Engineering - Discussion
Discussion Forum : Waste Water Engineering - Section 1 (Q.No. 27)
27.
A sewer pipe contains 1 mm sand particles of specific gravity 2.65 and 5 mm organic particles of specific gravity 1.2, the minimum velocity required for removing the sewerage, is
Discussion:
16 comments Page 1 of 2.
Ajay Kumar Yadav said:
2 years ago
0. 4m/s is the correct answer.
(1)
Masoom said:
6 years ago
Thank you @Sunil.
Nagdive said:
7 years ago
Thank you @Sunil And @Hemanth.
Hemanth said:
7 years ago
@All
Here, s sand particle up to 1mm and organic particles up to 5mm, there is a condition for this one min velocity of 0.45 m/sec and Max 0.9m/sec.
Hence no need to calculate anything.
And @Neethu, the correct formula is;
Vs=√((8k/f)*(s-1)*g*d) this is the right one.
Here, s sand particle up to 1mm and organic particles up to 5mm, there is a condition for this one min velocity of 0.45 m/sec and Max 0.9m/sec.
Hence no need to calculate anything.
And @Neethu, the correct formula is;
Vs=√((8k/f)*(s-1)*g*d) this is the right one.
(5)
Pavani said:
7 years ago
According to me, it is 0.5.
Randos said:
7 years ago
Check the unit. @Sunil.
Dipan said:
7 years ago
No, it is wrong @Sunil Gupta.
@Neethu
Thanks for your information.
This is the correct self-cleaning velocity and we get this formula 0.4 for organic particle and .42 for sand but the minimum self-cleaning velocity is 0.45 so we take the value 0.4.
@Neethu
Thanks for your information.
This is the correct self-cleaning velocity and we get this formula 0.4 for organic particle and .42 for sand but the minimum self-cleaning velocity is 0.45 so we take the value 0.4.
(2)
Dheerak singh said:
8 years ago
V=√k(gd (s-1)).
=√4.5 (10*.005 (1.2-1)).
=√4.5 (10*.005 (1.2-1)).
Ovizit Saha said:
8 years ago
Thanks @ Sunil Gupta.
RAVI YADAV said:
9 years ago
@ALL.
Use Neethu's formulae for solve this.
Thanks @Neethu.
Use Neethu's formulae for solve this.
Thanks @Neethu.
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