# Civil Engineering - Waste Water Engineering - Discussion

### Discussion :: Waste Water Engineering - Section 6 (Q.No.23)

23.

Pick up the correct statement from the following :

 [A]. Maximum daily flow = 2 times the average daily flow [B]. Maximum daily flow = x average daily flow [C]. Sewers are designed for minimum permissible velocity at minimum flow [D]. All the above.

Explanation:

No answer description available for this question.

 Anand Kumar said: (Sep 26, 2016) In option A and B it can be only one correct. Both indicate the same thing so option A is right.

 Gajan Rana said: (Apr 24, 2017) In option B it's "Minimum Daily flow".

 Engr said: (May 4, 2017) B is Min Daily flow.

 Raj said: (Aug 19, 2018) Thanks for giving the explanation.

 Shivam said: (Aug 25, 2018) Thanks for explaining it.

 Zaid said: (Oct 1, 2018) only option B is correct

 Er Nk said: (Feb 1, 2019) Option B should be - Minimum daily flow = 2/3 x Average daily flow.

 Anirban Roy said: (Aug 3, 2020) Max daily flow= 2 * avg daily flow. Min daily flow= 2/3 * avg daily flow. Max hourly flow= 3 * avg daily flow. Min belt flow= 1/3 * avg daily flow.