Civil Engineering - Waste Water Engineering - Discussion


Pick up the correct statement from the following :

[A]. Maximum daily flow = 2 times the average daily flow
[B]. Maximum daily flow = x average daily flow
[C]. Sewers are designed for minimum permissible velocity at minimum flow
[D]. All the above.

Answer: Option D


No answer description available for this question.

Anand Kumar said: (Sep 26, 2016)  
In option A and B it can be only one correct. Both indicate the same thing so option A is right.

Gajan Rana said: (Apr 24, 2017)  
In option B it's "Minimum Daily flow".

Engr said: (May 4, 2017)  
B is Min Daily flow.

Raj said: (Aug 19, 2018)  
Thanks for giving the explanation.

Shivam said: (Aug 25, 2018)  
Thanks for explaining it.

Zaid said: (Oct 1, 2018)  
only option B is correct

Er Nk said: (Feb 1, 2019)  
Option B should be - Minimum daily flow = 2/3 x Average daily flow.

Anirban Roy said: (Aug 3, 2020)  
Max daily flow= 2 * avg daily flow.
Min daily flow= 2/3 * avg daily flow.
Max hourly flow= 3 * avg daily flow.
Min belt flow= 1/3 * avg daily flow.

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