Civil Engineering - Waste Water Engineering - Discussion

Discussion Forum : Waste Water Engineering - Section 6 (Q.No. 23)

Waste Water Engineering

23.

Pick up the correct statement from the following :

Maximum daily flow = 2 times the average daily flow

Minimum daily flow =

x average daily flow

Sewers are designed for minimum permissible velocity at minimum flow

All the above.

Answer: Option

Explanation:

No answer description is available. Let's discuss.

Discussion:

3 comments Page 1 of 1.

Anirban Roy said: 5 years ago

Max daily flow= 2 * avg daily flow.
Min daily flow= 2/3 * avg daily flow.
Max hourly flow= 3 * avg daily flow.
Min belt flow= 1/3 * avg daily flow.

(2)

Shivam said: 7 years ago

Thanks for explaining it.

Raj said: 7 years ago

Thanks for giving the explanation.

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