# Civil Engineering - UPSC Civil Service Exam Questions - Discussion

19.

A sailor, standing on the deck of a ship, just sees the light beam from a lighthouse on the shore. If the height of the sailor's eye and of the light beam at the lighthouse, above the sea level, are 9 m and 25 m respectively, what is the distance between the sailor and the lighthouse ?

 [A]. 29.8 km [B]. 31.1 km [C]. 31.9 km [D]. 33.2 km

Explanation:

No answer description available for this question.

 Chhaya said: (May 31, 2017) Here, (25/0.0675)^0.5 + (9/0.0675)^0.5 = 31.1.

 Raj said: (Jun 25, 2017) Will you please explain in detail?

 Ravi said: (Jul 9, 2017) Explain me, please.

 Shreya said: (Nov 4, 2017) D = sqrt(H/0.06735). D = sqrt(25/0.06735) + sqrt(9/0.06735) = 30.82.

 Phani said: (Apr 28, 2018) D = 3.855(25^0.5 + 9^0.5), = 30.85 ~~ 31.1.

 Ashish K. said: (Jan 1, 2019) H=.0675d2. Hence d= H/0.0675. D=d1+d2, = 25/.0675 + 9/0.0675. 31.1km.

 Poonam said: (Aug 13, 2021) Use formula Height = 0.0673 x d^2. Here H1 abd H2 are given 25 and 9 respectively, Find d1 and d2. Then D = d1+ d2.