# Civil Engineering - UPSC Civil Service Exam Questions - Discussion

Discussion Forum : UPSC Civil Service Exam Questions - Section 14 (Q.No. 19)

19.

A sailor, standing on the deck of a ship, just sees the light beam from a lighthouse on the shore. If the height of the sailor's eye and of the light beam at the lighthouse, above the sea level, are 9 m and 25 m respectively, what is the distance between the sailor and the lighthouse ?

Discussion:

7 comments Page 1 of 1.
Poonam said:
3 years ago

Use formula Height = 0.0673 x d^2.

Here H1 abd H2 are given 25 and 9 respectively,

Find d1 and d2.

Then D = d1+ d2.

Here H1 abd H2 are given 25 and 9 respectively,

Find d1 and d2.

Then D = d1+ d2.

Ashish k. said:
6 years ago

H=.0675d2.

Hence d= H/0.0675.

D=d1+d2,

= 25/.0675 + 9/0.0675.

31.1km.

Hence d= H/0.0675.

D=d1+d2,

= 25/.0675 + 9/0.0675.

31.1km.

(1)

Phani said:
6 years ago

D = 3.855(25^0.5 + 9^0.5),

= 30.85 ~~ 31.1.

= 30.85 ~~ 31.1.

(2)

Shreya said:
7 years ago

D = sqrt(H/0.06735).

D = sqrt(25/0.06735) + sqrt(9/0.06735) = 30.82.

D = sqrt(25/0.06735) + sqrt(9/0.06735) = 30.82.

Ravi said:
7 years ago

Explain me, please.

Raj said:
7 years ago

Will you please explain in detail?

Chhaya said:
7 years ago

Here, (25/0.0675)^0.5 + (9/0.0675)^0.5 = 31.1.

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